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zubka84 [21]
3 years ago
11

?????????????????????????????????????????????????????????????????/

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
6 0
I am 90% sure it is 10
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Find the value of x , if log₂ [log₅ (log₃x)] = 0
Lina20 [59]
\log_2 (\log_5( \log_3x)) = 0\\
D:x>0 \wedge \log_3x>0 \wedge \log_5(\log_3x)>0\\
D:x>0\wedge x>1 \wedge\log_3x>1\\
D:x>1 \wedge x>3\\
D:x>3\\
\log_5(\log_3x)=1\\
\log_3x=5\\
x=3^5\\
x=243
3 0
3 years ago
Carol sold twice as many magazine subscriptions as Jennifer. If Carol and Jennifer sold 90 subscriptions in all, how many subscr
goblinko [34]
Hello there!

Carol would have sold 60 subscriptions and Jenifer would have sold 30

The correct answer is option D, 60

I hope this help!
3 0
3 years ago
Give an example of an absolute value inequality whose answers falls between two values. Give an example of an absolute value ine
mel-nik [20]

Answer:

A) Suppose we have an onedimensional situation.

in the 0 of our x-axis, we have a fruit tree, and we want to rest at a distance no bigger than 6 ft of the tree, then all the possible positions of our resting place are:

x ∈(-6ft, 6ft)

we can write this as: IxI < 6ft

b) now we think the opposite situation, we want to rest at least 6ft away from the tree, then we have that:

x ∉  [-6ft, 6ft].

or IxI > 6ft.

So you can see that the difference in those two cases is if we want to be "inside a given range" (for the first case) or "outside a given range" (for the second case).

8 0
3 years ago
The elevator at the state capital has a maximum weight capacity of 2000 pounds. If there are 3
Korolek [52]

Answer:

Step-by-step explanation:

Maximum capacity of the elevator = 2000 pounds

Combined weight of the elevator = 428 pounds

A). Let the possible weights that can be added to the elevator = w pounds

B). Therefore, inequality representing this situation will be,

    428 + w < 2000

C). By solving the given inequality,

    (428 + w) - 428 < 2000 - 428

    w < 1572 pounds

    Now we draw this inequality on a number line.

3 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min, and its coarseness is such that it forms a pile in the shap
pogonyaev

Answer:

Rate of increase in height =\frac{dh}{dt}=0.3156ft/min

Step-by-step explanation:

we know that volume of a cone is given by

V=\frac{1}{12}\pi d^{2}h

It is Given that diameter equals height thus we have

V=\frac{1}{12}\pi h^{2}h\\\\V=\frac{1}{12}\pi h^{3}

Differentiating both sides with respect to time we get

\frac{dV}{dt}=\frac{1}{12}\pi \frac{dh^{3}}{dt}\\\\\frac{dV}{dt}=\frac{1}{12}\pi(3h^{2}\frac{dh}{dt})

Applying values and solving for \frac{dh}{dt} we get

\frac{dh}{dt}=\frac{12\frac{dV}{dt}}{3\pi h^{2}}\\\\\frac{dh}{dt}=0.3156ft/min

8 0
3 years ago
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