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yuradex [85]
4 years ago
8

Which expression defines the arithmetic series 2.3 + 2.6 + 2.9 + . . . for five terms?

Mathematics
2 answers:
olga55 [171]4 years ago
5 0
So a sub n=2.3+(n-1)0.3
That's in an arithmetic sequence
heres a pic to help

lawyer [7]4 years ago
4 0
2.3 plus 2.6 plus 2.9 plus 3.2 plus 3.5
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What are transformation possible to change f(x) to g(x) on graph linear equation
Korolek [52]

Answer:

<h2>Vertical stretch or compression and vertical shift.</h2>

Step-by-step explanation:

When we talk about the transformation of functions, we can mention stretching, rotating, dilating, shifting. However, when we want to transform linear functions, there are only two transformations that are worthy in that case, those are vertical stretch or compression and vertical shift.

Now, you may ask, why only vertical transformation? the reason behind that is because horizontal transformation would give the exact same result because it's only a straight line which we are transforming.

Another common question would be, why only two transformations? it's because with these two you can get all the results because it's a straight line.

The image attached shows examples of this.

8 0
3 years ago
Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff
liubo4ka [24]

Answer:

There is only one real zero and it is located at x = 1.359

Step-by-step explanation:

After the 4th iteration the solution was repeating the first 3 decimal places.  The formula for Newton's Method is

x_{n}-\frac{f(x_{n}) }{f'(x_{n}) }

If our function is

f(x)=x^5+x-6

then the first derivative is

f'(x)=5x^4+1

I graphed this on my calculator to see where the zero(s) looked like they might be, and saw there was only one real one, somewhere between 1 and 2.  I started with my first guess being x = 1.

When I plugged in a 1 for x, I got a zero of 5/3.  

Plugging in 5/3 and completing the process again gave me 997/687

Plugging in 997/687 and completing the process again gave me 1.36976

Plugging in 1.36976 and completing the process again gave me 1.359454

Plugging in 1.359454 and completing the process again gave me 1.359304

Since we are looking for accuracy to 3 decimal places, there was no need to go further.

Checking the zeros on the calculator graphing program gave me a zero of 1.3593041 which is exactly the same as my 5th iteration!

Newton's Method is absolutely amazing!!!

5 0
4 years ago
Write this expression in radical form
Lerok [7]
It is already in radical form......... but, if you want us to make it into exponential form, it is 8x^(2/3)
3 0
4 years ago
70% of the 100 students in a middle school cafeteria bought their lunch. Some of the students that bought there lunch leave the
Fittoniya [83]
600 because 60 percent of 100 is 600
5 0
3 years ago
Read 2 more answers
The legs of an isosceles triangle have lengths x + 1 and -x + 7 . The base has length 3x - 3. What is the length of the base?
In-s [12.5K]
Since you've told us that this is an isosceles triangle, we know that the 'legs' have equal length.  So we can write

                                                      x + 1 = -x + 7

Add 'x' to each side:                  2x + 1 =       7

Subtract  1  from each side:      2x       =       6

Divide each side by  2 :                x      =       3

Now, if the length of the base is   3x - 3 ,
that length is

                                   3(3) - 3  =  6  .
8 0
3 years ago
Read 2 more answers
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