Answer:
Your answer is -5
Step-by-step explanation:
On paper;
What are transformation possible to change f(x) to g(x) on graph linear equation
1 answer:
Answer:
<h2>Vertical stretch or compression and vertical shift.</h2>Step-by-step explanation:
When we talk about the transformation of functions, we can mention stretching, rotating, dilating, shifting. However, when we want to transform linear functions, there are only two transformations that are worthy in that case, those are vertical stretch or compression and vertical shift.
Now, you may ask, why only vertical transformation? the reason behind that is because horizontal transformation would give the exact same result because it's only a straight line which we are transforming.
Another common question would be, why only two transformations? it's because with these two you can get all the results because it's a straight line.
The image attached shows examples of this.
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Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,
Answer:
Volume:
Ratio:
Step-by-step explanation:
First of all, we need to find the volume of the hemispherical tank.
The volume of a sphere is given by:
where
r is the radius of the sphere
V is the volume
Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:
Now we want to find the ratio between the volume of the hemisphere and its surface area.
The surface area of a sphere is
For a hemisphere, the area of the curved part of the surface is therefore half of this value, so . Moreover, we have to add the surface of the base, which is
. So the total surface area of the hemispherical tank is
Therefore, the ratio betwen the volume and the surface area of the hemisphere is