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3 years ago

Which graph shows a line with positive slope that passes through the point (r, s)?

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

5 0

r is the x coordinate and s is the y coordinate. Positive slopes go from lower left to upper right, like going up stairs or up a hill. The line that goes through (r, s) that is positive is line B.

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How do i do this?????????

Gnom [1K]

Answer:

x≥5

Step-by-step explanation:

-1 ≥ x/-5

x/-5 ≤ -1

x(-1)/5 ≥ (-1) (-1)

x/5 ≥ 1

5x/5 ≥ 1 ×5

x ≥ 5

I'm not sure but I tried.

For the graph: you can draw a line about 15cm, put 0 at the start then after 5cm put 5 then 10 at 10cm and 15 at the end. At 5 put • that's the starting and go all the way to 15 and add > to show that the line continues. I'm not good at explaining but I hope it helps.

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schepotkina [342]

Answer:

Step-by-step explanation:

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3 years ago

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2 years ago

Find all constants a such that the vectors (a, 4) and (2, 5) are parallel.

Nezavi [6.7K]

Answer:

$\displaystyle a = \frac{8}{5}$ .

Step-by-step explanation:

Two vectors $(x_1,\, y_1)$ and $(x_2,\, y_2)$ are parallel to one another if and only if the ratio between their corresponding components are equal:

$\displaystyle \frac{x_1}{x_2} = \frac{y_1}{y_2}$ .

Equivalently:

$\displaystyle \frac{x_1}{y_1} = \frac{x_2}{y_2}$ .

For the two vectors in this equation to be parallel to one another:

$\displaystyle \frac{a}{4} = \frac{2}{5}$ .

Solve for $a$ :

$\displaystyle a = \frac{8}{5}$ .

$\displaystyle \frac{8}{5}$ would be the only valid value of $a$ ; no other value would satisfy the $\displaystyle \frac{x_1}{y_1} = \frac{x_2}{y_2}$ equation.

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Mkey [24]

Answer:

A goes through the points

Step-by-step explanation:

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