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mamaluj [8]
4 years ago
12

in circle O, diameter AOB is drawn and point C is located on the circle such that CA=12 and CB=16. What is the length of the rad

ius of circle O?
Mathematics
1 answer:
kotegsom [21]4 years ago
5 0

Answer:

radius = 10

Step-by-step explanation:

As AB is the diameter of the circle, the angle ACB inscribes an arc of 180 degrees, so it is a 90 degrees angle, then the triangle ACB is a right triangle, with hypotenusa AB.

We can find the length of the diameter AB using the Pythagoras' theorem:

AB^2 = CA^2 + CB^2

AB^2 = 12^2 + 16^2 = 400

AB = 20

The radius of the circle is half the diameter, so the radius is 20 / 2 = 10

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Answer:

The slope is zero. Since both coordinates have the y-value of -1, they are on the same line on the graph and form a horizontal line with a slope of zero. (a straight horizontal line)

Step-by-step explanation:

use the formula

(y2-y1)/(x2-x1)

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so where (x1,y1) (x2,y2) can be subsituted

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3 years ago
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Vladimir79 [104]

Answer:

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3 years ago
S(n) = -2n +1<br> f(10) =
topjm [15]

Answer: f(10) = -19

Step-by-step explanation:

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2. Multiply 10 by -2

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3. Addition

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3 0
3 years ago
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nikitadnepr [17]

Answer:

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The approximate lower class limit of the first class is the lowest score we have in the first class = 110

The approximate upper class limit of the first class is the closest highest score that fall within the first class and is below the lower limit of the second class. Thus approximate upper class limit of the first class = 129

8 0
3 years ago
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Answer:

c

Step-by-step explanation:

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