3 years ago

10+x=5(1/5x+2) Equations with infinite and no solution

Mathematics

1 answer:

Luden [163]3 years ago

6 0

Answer:

Infinitely many solutions.

Step-by-step explanation:

10+x=5(1/5x+2)

10+x=x+10

infinitely many solutions

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Solve for all values of x by factoring

oksian1 [2.3K]

Answer:

x= 0,5

Step-by-step explanation:

You have to move all the terms to the left side and set them equal to zero. Then set each factor equal to zero.

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2 years ago

1. Angle BAC = 35° and angle BCA = 20°. What is the measure of angle BAD?

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Divide: 4/15÷8/25. What is the answer?

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4/15 = 0.267
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3 years ago

Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z

Oliga [24]

Given the expression

$54m^3n\:+\:81m^4n^2$

Apply exponent rule: $a^{b+c}=a^ba^c$

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn$ ∵ $m^4n^2=m^3mnn$

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

$=2\cdot \:27m^3n+3\cdot \:27m^3mnn$

Factor out the common term: 27m³n

$=27m^3n\left(2+3mn\right)$

Therefore,

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)$

Given the expression

$15x^2y^3z+25x^3y^2z+35x^2y^2z$

Apply exponent rule: $a^{b+c}=a^ba^c$

$15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z$

Rewrite as

$=3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z$

Factor out common term 5y²x²z

$=5y^2x^2z\left(3y+5x+7\right)$

Therefore,

$15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)$

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Range is 6 and the mode is 8

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