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forsale [732]
2 years ago
9

How much work must be done on a 1000kg car to increase its speed from 1 m/s to 2 m/s

Mathematics
1 answer:
worty [1.4K]2 years ago
6 0

Answer: its is you figer it out okay haha

Step-by-step explanation: im jokeing

Kinetic energy = 1/2 M V2

At the lower speed, the car's KE is (500) (1)2 = 500 joules

At the higher speed, the car's KE is (500) (2)2 = 2,000 joules

The difference is the energy i.e. the work you have to put into it

to raise the speed from 1 m/s to 2 m/s.

(2,000 - 500) = 1,500 joules there u go :D

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Which statement about the polygons is true?
tatyana61 [14]

Polygon A is similar to Polygon B because Polygon B is a dilation of Polygon A.

6 0
2 years ago
Three airlines serve a small town in Ohio. Airline A has 52% of all scheduled flights, airline B has 27% and airline C has the r
julia-pushkina [17]

Answer:

Step-by-step explanation:

Given that three airlines serve a small town in Ohio. Airline A has 52% of all scheduled flights, airline B has 27% and airline C has the remaining 21%.

Their on-time rates are 83%, 66%, and 36%, respectively.

Airlines A B C  

   

Flights                52%                  27%             21%   100%

On time rates  83%                  66%         36%  

   

Flight*online rates 43.1600% 17.8200% 7.5600% 68.5400%

Thus the above table shows the product of no of flights and on time rates.

Prob it was airline A given it left on time

= \frac{43.16}{68.54} \\=0.6297

4 0
3 years ago
Helppppp plzzzz ASAP!!!!!!<br> Thank you!!!!!!
Zielflug [23.3K]

Answer:

option 4.

16 square units

Step-by-step explanation:

as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.

P = (2 , 4)

S = (4 , 2)

we have to subtract the values ​​of p from s

PS = (4 - 2  , 2 - 4)

PS = (2 , -2)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

PS^2 = 2^2 + -2^2

PS = √ 4 + 4

PS = √8

PS = 2√2

S = (4 , 2)

R = (8 , 6)

SR = (8-4  ,  6-2)

SR = (4 , 4)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

SR^2 = 4^2 + 4^2

SR = √ (16 + 16)

SR = √32

SR = 4√2

having the values ​​of 2 of its sides we multiply them and obtain their area

PS * RS = Area

2√2 * 4√2 =

16

3 0
3 years ago
Solve by Substitution<br> Show Steps<br> −2x + 3y + 5z = −21<br> −4z = 20<br> 6x − 3y = 0
Anarel [89]

−2x + 3y + 5z = −21

−4z = 20

6x − 3y = 0

do -4z=20 first

divide both sides by -4 to get z by itself

-4z/-4=20/-4

z=-5

Use z=-5 into −2x + 3y + 5z = −21

-2x+3y+5(-5)=-21

-2x+3y-25=-21

move -25 to the other side

sign changes from -25 to +25

-2x+3y-25+25=-21+25

-2x+3y=4

6x-3y=0

find x by eliminating y

Add the equations together

-2x+6x+3y+(-3y)=4+0

-2x+6x+3y-3y=4

4x=4

Divide by 4 for both sides

4x/4=4/4

x=1

Use x=1 into 6x − 3y = 0

6(1)-3y=0

6-3y=0

Move 6 to the other side

6-6-3y=0-6

-3y=-6

Divide both sides by -3

-3y/-3=-6/-3

y=2

Answer:

(1, 2, -5)

5 0
3 years ago
Read 2 more answers
Number 4 please !! due tomorrow
Minchanka [31]

Answer:

c is the answer




4 0
2 years ago
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