Answer:
see explanation
Step-by-step explanation:
let pq = x
given oq - pq = 1 then oq = 1 + x
Using Pythagoras' identity, then
(oq)² = 7² + x²
(1 + x)² = 49 + x² ( expand left side )
1 + 2x + x² = 49 + x² ( subtract 1 from both sides )
2x + x² = 48 + x² ( subtract x² from both sides )
2x = 48 ( divide both sides by 2 )
x = 24 ⇒ pq = 24
and oq = 1 + x = 1 + 24 = 25 ← hypotenuse
sinq = =
cosq = =
Here's what I mean when I write <em>x/</em><em>2</em><em> </em><em>JUST </em><em>IN </em><em>CASE.</em>
а.
Let the total number of pencils be x, then this implies that Maggie received <em>x/</em>2 pencils from Katie. Maggie keeps 5 and give the rest to Jamil, this means
that Jamil receives
<em>x/</em>2-5 pencils.
b. Expression of pencils given to Jamil is: <em>x/</em>2-5
Substitute <em>x</em><em>=</em><em>1</em><em>6</em><em> </em>in this expression: <em>x/</em>2-5
Simplify and evaluate: = 8-5= 3
Maggie gives 3 pencils to Jamil.
c. Expression of pencils given to Jamil is: x/2-5 to
Equate this expression with 1 to form an equation and solve for <em>x</em> all, the total
number of pencils if Jamil received 1 pencil:
<em>x/</em>2 - 5 = 1
Solve for x:
<em>x</em> = 2(1+ 5)
Evaluate:
<em>x</em> = 2(6) = 12
Katie had 12 pencils if Jamil received 1 pencil.
RESULT
a. Expression of number of pencils given to Jamil is <em>x</em>/2-5, where x is total number of pencils.
b. Maggie gives 3 pencils to Jamil.
c. Katie had 12 pencils if Jamil received 1 pencil.
