Step-by-step explanation:
Hey there!
<u>Firstly </u><u>find </u><u>slope </u><u>of</u><u> the</u><u> </u><u>given</u><u> equation</u><u>.</u>
Given eqaution is: 3x + 2y = 5.......(i)
Now;
Therefore, slope (m1) = -3/2.
As per the condition of parallel lines,
Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.
The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;
(y-y1) = m2 (x-x1)
~ Keep all values.
~ Simplify it.
Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.
<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
6*2=12
32-12=20
20/2=10.
Perimeter is all the way around an object. So take 6 two times and minus that from 32. Answer of that divide by 2 to get the length. Length of one side is 10 ft.
Answer:
(-1,6)
Explanation:
use (y1-y2), (x1-x2)
<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.
In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>
49–2ax –a^2–x^2
Extract the negative sign
= 49 - (a^2 +2ax +x^2)
Factor using a^2 + 2ab + b^2 = (a+b)^2
= 49 - (a+x)^2
Factor using a^2 - b^2 = (a-b)(a+b)
= ( 7- (a + x)) * (7 + (a + x))
= ( 7- a - x) * (7 + a + x)
