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3 years ago

Thank you for help with the problem

Mathematics

1 answer:

Lerok [7]3 years ago

6 0

I don't know who you are talking to or what you want me to answer

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Reynaldo rode his bike 2 miles north and 3 miles east. Which equation should he ise to find the distance, d, that takes him dire

ValentinkaMS [17]

Pythagorean theorem - a^2 + b^2 = c^2

2^2+3^2 = d^2
d^2 = 13
d= square root of 13

6 0

3 years ago

Read 3 more answers

Negative 7 bigger or smaller than negative 8

dalvyx [7]

-7 is bigger than -8

4 0

3 years ago

Read 2 more answers

Help! Please answer screen shot! Brainliest, stars, and hearts! Please help!

lutik1710 [3]

Answer:

since 0=noon

and 15 secs=25% of a min

plot the point on the very first line to the right of 0

(the tiny line)

Step-by-step explanation:

8 0

2 years ago

A recipe needs 3/4 cup of water for every 2 cups of flour. If you to use 6 cups of flour, how much water will you need?

Diano4ka-milaya [45]

Answer:

2 1/4 or 2.25

Step-by-step explanation:

2*3= 6

3/4*3= 2 1/4

4 0

3 years ago

Need help with homework

motikmotik

We have two points describing the diameter of a circumference, these are:

$\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}$

Recall that the equation for the standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

$M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Now, we replace and solve:

$\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}$

The center of the circle is (-8,-7), so:

$\begin{gathered} h=-8 \\ k=-7 \end{gathered}$

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

$r^2=\Delta x^2+\Delta y^2$

In this case, we will solve the delta with the center coordinate and the B coordinate.

$\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}$

Therefore, the equation for the standard form of a circle is:

$\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}$

In conclusion, the equation is the following:

$(x+8)^2+(y+7)^2=25$

4 0

1 year ago