<img src="https://tex.z-dn.net/?f=100%20%5Ctimes%2068%20%5Cdiv%2015" id="TexFormula1" title="100 \times 68 \div 15" alt="100 \ti

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3 years ago

15

mes 68 \div 15" align="absmiddle" class="latex-formula">

1 answer:

goldfiish [28.3K]3 years ago

4 0

The answer is 453 rounded

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3 years ago

What requirements must be satisfied? select all that apply.

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In order to satisfy the requirement, this are the following that is required;First, at least one observation must be above or below 90 seconds. Second is ether the population is normally distributted or greater than (>) 30, or maybe both.
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2 years ago

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DochEvi [55]

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2 years ago

At a certain high school, 15 students play stringed instruments and

Aleks [24]

Answer:

<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N( $A \cup B$ )' = 5

<u>To find:</u>

The probability that a randomly selected students plays both = ?

<u>Solution:</u>

Total Number of students = N(A)+N(B)+N( $A \cup B$ )' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

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$N(A\cap B) =0$

Formula for probability of an event E can be observed as:

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So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.

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2 years ago

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kotykmax [81]

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2 years ago

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