Answer:
The price of the cell phone without the coupon= $500
Step-by-step explanation:
Step 1: Express discounted amount
The discounted amount can be expressed as a function of the original cost of the phone as follows;
D=r×A
where;
D=discounted amount
r=coupon rate
A=original price of the cell phone before the coupon
In our case;
r=45%=45/100=0.45
A=a
replacing;
Discounted amount=(0.45×a)=0.45 a
Step 2: Amount she pays up
Amount she pays=Original cost of cell phone-discounted amount
where;
Amount she pays= $275
original cost of cell phone=a
discounted amount=0.45 a
replacing;
$275=a-0.45 a
0.55 a=275
a=275/0.55
a=500
The price of the cell phone without the coupon= $500
15, 18, 21
i don't know the other one, sorry
A fraction is a way to describe a part of a whole. A fraction can be a proper fraction, an improper fraction, or a mixed fraction.
<h3>What is a Fraction?</h3>
A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.
A fraction consists of two whole numbers, a number that is above the fraction line which is the Dividend, while the number that is below the fraction line is known as the denominator and is the divisor. The result or the answer which we get when we solve the fraction is the factor or can be said, it is the quotient of the operation.
Suppose there is a fraction, a/b which is equal to c, then,
a is the dividend, b is the divisor, and c is the quotient.
Learn more about Fraction:
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Answer: 15 boys
Explanation: ratio 5:7
5 + 7 = 12
Number of boys = 5/12 × 36
Part A:
<span>a system of inequalities that only contain points D and E in the overlapping shaded regions is
5y + 2x > 12
2y - x < 12
Part B:
To verify that points D and E are solutions to the system of inequalities, we plug in the coordinate points of points D and E into the system of ineaqualities.
Part C:
</span>To <span>identify the schools that Timothy is allowed to attend we plug in the coordinate values of the points to see which satisfies the inequality y < 3x - 3. Thus Timothy is allowed to attend schools C and F.</span>