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Lady bird [3.3K]
3 years ago
13

WILL GIVE 30 POINTS, ANSWER QUICKLY BEFORE SOMEONE STEALS THE POINTS!

Mathematics
2 answers:
netineya [11]3 years ago
6 0

Answer: the answer to 9 is D


Step-by-step explanation: it is


vichka [17]3 years ago
3 0

Answer:

one quesion at a time plz

Step-by-step explanation:


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Six of King Arthur’s knights are sitting around the Round Table eating peanuts. Since each knight suspected the others of not sh
Bogdan [553]

Answer:

You must add the numbers of the neigbors from the one who counted 52, subtract the number of the one who is opposide and divided by 2.

So i calculate

(44 + 60 - 28) = 38

The knight who counted 52 has 38 peanuts.

5 0
2 years ago
Read 2 more answers
Jonas wants to serve serve 48 people one cup of tea each. How many gallons of tea must he prepare?
Aleks04 [339]

Answer:

3 gallons

Step-by-step explanation:

1 gallon=16 cups

48÷16=3

3 gallons makes 48 cups

6 0
3 years ago
Question? <br><br> rewrite using standard notation 9.4 x 10^1 ????
grigory [225]
In general if multiplying, move decimal to RIGHT by whatever the exponent is.
In this example 10^1, the exponent = 1

9.4 with decimal moved 1 place to right = 94
3 0
3 years ago
(7x-12)+(13-2x)<br><img src="https://tex.z-dn.net/?f=%287x%20-%2012%29%20%2B%20%2813%20-%202x%29" id="TexFormula1" title="(7x -
Julli [10]
The answer is : 5x+1
5 0
3 years ago
Use the intermediate value theorem to prove that there is a positive number c such that c2 = 2.
schepotkina [342]

So lets try to prove it,

So let's consider the function f(x) = x^2.

Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).

Using the Intermediate Value Theorem,

it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.

Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.

Learn more about Intermediate Value Theorem on:

brainly.com/question/11377865

#SPJ4

6 0
1 year ago
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