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3 years ago

Estimate and then find all of the values.

2 answers:

8 0

300,000-80,000 equals 220,000

60,000+500,000 = 560,000

90,000-50,000 = 40,000

5000+100 = 5100

17,000-5000 equals 12,000

8,000 +100 = 8100

10,000 - 1000 = 9000

1000+500 = 1500

7000-100 = 6900

100,000 + 100 equals 100,100

I don’t know if I’m completely correct so please go over the answers and I went in order just so you know

Stells [14]3 years ago

5 0

Sorry wish I knew this one

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A soft drink machine outputs a mean of 2323 ounces per cup. The machine's output is normally distributed with a standard deviati

viktelen [127]

Answer:

Area under the normal curve: 0.6915.

69.15% probability of putting less than 24 ounces in a cup.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 23, \sigma = 2$

You have been asked to calculate the probability of putting less than 24 ounces in a cup.

pvalue of Z when X = 24. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{24 - 23}{2}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915

Area under the normal curve: 0.6915.

69.15% probability of putting less than 24 ounces in a cup.

5 0

3 years ago

1million got how many zeros?

Alexxandr [17]

Answer:

it would get 6 zeros

Step-by-step explanation:

hope it helps :)

6 0

3 years ago

What is the value of a3 in the sequence? a3 the 3 is squared below of a

kkurt [141]

Answer:

Option D is correct.

$a_3 = \frac{-1}{2}$

Step-by-step explanation:

The sequence is in the form of :

$a_1, a_2, a_3, a_4, .......$

where

$a_1$ represents the First term.

$a_2$ represents the Second term.

$a_3$ represents the Third term.

$a_4$ represents the Fourth term and so on.....

we have to calculate the $a_3$ in the given sequence:

Given the sequence: $-4 , -2, -\frac{1}{2} , -\frac{1}{4}, ......$

$a_3 = \frac{-1}{2}$

Therefore, the third term $a_3 = \frac{-1}{2}$

7 0

4 years ago

Scores of an IQ test have a bell-shaped distribution with a mean of and a standard deviation of . Use the empirical rule to det

Oduvanchick [21]

Complete question is;

Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 13. Use the empirical rule to determine the following.

(a) What percentage of people has an IQ score between 87 and 113?

(b) What percentage of people has an IQ score less than 74 or greater than 126?

Answer:

A) 68% of the people had an IQ score between 87 and 113

B) 5% of the people had IQ scores less than 74 and greater than 126.

C) 0.15% had an IQ score greater than 139

Step-by-step explanation:

We are given;

Mean; x¯ = 100

Standard deviation; σ = 13

According to the empirical rule in statistics;

>> 68% of the data lies within one standard deviation of the mean

>> 95% of the data lies within two standard deviations of the mean

>> 99.7% of the data lies within three standard deviations

A) We want to find the percentage of people with an IQ score between 87 and 113.

Within one standard deviation, we have;

x¯ ± σ

>> (100 - 13), (100 + 13)

>> (87, 113) which is the range we are looking for.

Thus, 68% of the people had an IQ score between 87 and 113

B) we want to find percentage of people has an IQ score less than 74 or greater than 126.

Let's first find those who had between 74 and 126.

Let's use two standard deviations within the mean.

x¯ ± 2σ

>> (100 - (2×13)), (100 + (2×13))

>> (74, 126) which is the range we are looking for.

So percentage that have IQ scores between 74 and 126 is 95%

Thus;

Percentage of those who had less than 74 and greater than 126 is;

P = 1 - 95%

P = 5%

C) we want to find the percentage of people that had an IQ score greater than 139.

Let's use the z-score formula;

z = (x¯ - μ)/σ

z = (139 - 100)/13

z = 39/13

z = 3

This means it is 3 standard deviations above the mean.

Thus;

Since it's one side outside the mean, then;

Percentage of people with an IQ score greater than 139 = (1 - 99.7%)/2 = 0.3%/2 = 0.15%

5 0

3 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary). (-1,8) and (8,5)

Cloud [144]

Your answer to is 9.5

4 0

3 years ago