So what do you need us to do for you?
Answer:
27 ft
the maximum height of the arrow is 27 ft
Step-by-step explanation:
Given;
The height of the arrow is given by the function;
h(t) = -16t^2 + 32t + 11
Maximum height is at point when dh(t)/dt = 0.
Differentiating h(t), we have;
dh/dt = -32t + 32 = 0
Solving for t;
-32t = -32
t = -32/-32 = 1
t = 1 (time at maximum height is t = 1)
Substituting t=1 into h(t), to determine the value of maximum height;
h(max)= -16(1^2) + 32(1) + 11
h(max) = 27 ft
the maximum height of the arrow is 27 ft.
That one in the san Andreas movie?
Vertical angles are congruent whether the lines are parallel or not.
Corresponding angles are congruent.
Alternate interior and alternate exterior angles are congruent.
1 & 4, 2 & 3, 3 & 6, 4 & 5, 1 & 8, 2 & 7, 5 & 8, 6 & 7, 3 & 7, 1 & 5, 2 & 6, 4 & 8
I think I got all of them!
