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LenKa [72]
3 years ago
12

Using GCF and the distributive property, write two equivalent expressions for 30+45?

Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0
5x15, 3x25 because 30+45=75 and both 5x15 and 3x25 equal 75
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Help me pls. Pls do this step by step. I will give he brainliest to the person who does it step by step.
Zanzabum

Answer:

x^2 - x^3 - 3x^2y - 3xy^2

Step-by-step explanation:

x^3 +y^3 - (x + y)^3​

Expand the expression

x^2 + y^3 - (x^3 + 3x^2y + 3xy^2 +y3)

Remove the parentheses

x^2 +y^3 -x^3 -3x^2y -3xy^2 - y^3

Remove the opposites

Answer:

x^2 - x^3 - 3x^2y - 3xy^2

Hope this Helps!

3 0
3 years ago
(-9) x 7? Can't figure it out​
mihalych1998 [28]
-56

Explain 9x7 is 56 then you add a negative. Please thanks and brainliest if correct!
3 0
3 years ago
PLEASE BE QUICKKK!!
elena-s [515]

Answer:

The Answer would be C, i think

Step-by-step explanation:

5 0
3 years ago
-2 3/7 - 1 2/3 show ur work!please
nataly862011 [7]

Answer:

-4 2/21

Step-by-step explanation:

-2 3/7 - 1 2/3

Change to improper fraction

-2 3/7 = -17/7

- 1 2/3 =-5/3

-17/7-5/3

L.C.M=21

-51-35/21

= -86/21

= -4 2/21

Hope it helps..

Please mark brainliest

7 0
1 year ago
Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo
bija089 [108]
<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by \sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}} provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}

\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}

\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}

\implies\sf{x=\frac{1 \pm\: 7}{4}}

Solving one by one,

\implies\sf{x=\frac{1 + \: 7}{4}}

\implies\sf{x=\frac{8}{4}}

\implies{\boxed{\bf{x=2}}}

________________

\implies\sf{x=\frac{1 - \: 7}{4}}

\implies\sf{x=\frac{-6}{4}}

\implies{\boxed{\bf{x=\frac{-3}{2}}}}

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

<em>________________________________</em>

Hope it helps!! (:

4 0
2 years ago
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