Answer:
The volume of water that remains on the cone is 523.6 cm³
Step-by-step explanation:
To solve this problem you have to keep in mind the formules that describes the volume of a cone and the volume of a sphere.
Volume of a cone = (πr²h)/3
Volume of a sphere = (4/3)πr³
So, if the base of the cone has a diameter of 10 cm, its radius is 5 cm. Its altitude is 10 cm. ⇒Volume = (πr²h)/3 ⇒ Volume = [π(5²)10) ⇒
Volume = 785.4 cm³. This is the initial volume of water.
Now if the sphere fits in the cone and half of it remains out of the water, the other half is inside the cone. Estimating the volume of the sphere and dividing it by two, you find the volume of water that was displaced.
Volume of a sphere = (4/3)πr³, here the radius is the same of the base of the cone (5 cm).
⇒ Volume = (4/3)π(5³) ⇒ Volume = 523.6 cm³ ⇒ The half of this volume is 261.8 cm³. This is the volume of water displaced.
⇒ The volume of water that remains on the cone is 523.6 cm³ (785.4 cm³- 261.8 cm³)
Answer:
V = 196 mm³
Step-by-step explanation:
( 7/21 )³ = V / 5292
343 / 9261 = V / 5292
9261 V = 343 * 5292
V = 196 mm³
Answer:
f(-3)=4
Step-by-step explanation:
Substitute x=-3 into the function
f(-3)=(-3)^2-5
f(-3)=9-5
f(-3)=4
One and seventy-five hundreths is how you say it in word form.
Example:
0.1234
1 is in the tenths place.
2 is in the hundreths place.
3 is in the thousandths place.
Answer:
(14502/h)inches²
Step-by-step explanation:
The Volume of a pyramid is calculated using the formula
Volume of a Pyramid = A × h/3
Where A =Area of the Base of the pyramid
h =pyramid height
We can derive the Formula for the base area of the pyramid
Therefore,
The Base area of the pyramid = V
÷ h/3 = 3× V/h
From the question we were given:
The Volume of a pyramid = 4834inches³
The height of the pyramid(h) was not given in the question hence we calculate with respect to the height.
The base area of the pyramid = 3 × V/h
= 3 × 4834inches³/h
Base Area of that pyramid = (14502/h)inches²
