The answer is <span>B.a wildfire breaks out in a forest, removing all remaining shelters for tree squirrels
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Hi! :)
Make a = q, aa (homozygous recessive) = q^2,
A = p, AA (homozygous dominant) = p^2, and
2pq = heterozygous
This was derived from p + q = 1
Therefore all a in pop (q) = 20% = .20
And all A in pop (p) = 80% = .80
Since the disease is homozygous recessive (affected), then aa = qq or q×q = q^2
q^2 = (.20)^2 = .040 = 4%
Answer: 4%
The synthesis of fatty acids starts with a preparratory phase in which acetyl CoA is translocated from mitochondria to the cytosol. However, it cannot pass through the membrane, so it is translocated as citrate that is cleaved to acetyl CoA and oxaloacetate.
In the cytosol, acetyl CoA is transformed to malonyl-CoA, that is, a three carbon compound. Fatty acid synthesis starts with the transfer of the acetyl group from acetyl-CoA to fatty acid synthase.
Two-carbon groups supplied by malonyl-CoA, are supplemented to the developing acyl chain in a series of steps involving condensation, reduction, and dehydration reactions. Elongation of the fatty acid chain ceases at 16 carbon atoms, after 7 cycles, as the free fatty acid is discharged.
20 babies were born in the ward, 10 of them had blue eyes and the other 10 had brown eyes.
% of blue eyes babies is 50% and % of brown eyes babies is also 50% (10/20*100).
<h3>What is a Dominant trait? </h3>
Brown eye color gene is a dominant trait, and it can express itself in pure breed condition as well as impure breed condition.
Blue eye color gene is recessive and can only express itself in pure breed recessive condition, the dominant gene repress the expression of the recessive gene phenotypically, but the genetic makeup remains the same.
Hence, the blue-eyed babies have pure breed recessive genotype and brown eyed babies have pure breed dominant genotype or genotype.
Learn more about Dominant and recessive traits
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Answer:
Looks hard
Explanation:
I dont know how to do this
