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densk [106]
4 years ago
5

Help..

Mathematics
1 answer:
Leona [35]4 years ago
7 0

Hey there!

In order for you to do this equation you have to do <u>PEMDAS</u>

  1. \bold{Parentheses, Exponents,Multiplication,Division,Addition,Subtraction}
  • \bold{\frac{1}{2}(7)(4)+6(5)}
  • \bold{\frac{1}{2}(7)=\frac{7}{2}}
  • \bold{\frac{7}{2}(4)=14}
  • \bold{6(5)=30}
  • \bold{14+30=44}
  • \boxed{\boxed{\bold{Answer\#1:44}}}

  • \bold{12(6)+\frac{1}{4}\times2^2}
  • \bold{12(6)=72}
  • \bold{2^2=4}
  • \bold{\frac{1}{4}\times4=1}
  • \bold{72+1=73}
  • \boxed{\boxed{\bold{Answer\#2:72}}}

Good luck on your assignment and enjoy  your day!

~\frak{LoveYourselfFirst:)}

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In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence
Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

\hat p =\frac{12}{300}=0.04

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CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

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*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

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Answer:

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then add 18.50 by 7/24

i hope this explains how i got my answer

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