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2 years ago

Explain the differences between adding and multiplying radical expressions using 2 examples you create.

1 answer:

6 0

When you multiply radical expressions you multiply the numbers under the radical symbols.3–√×7–√=21−−√
When you add radical expression you CANNOT add the numbers under the radical symbols.
3–√+7–√≠10−−√

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Answer:

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Step-by-step explanation:

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Answer:

the answer is 5,110 pounds

Step-by-step explanation:

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2 years ago

Simplify -9(1-10n) - 2(3n+9)

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Answer:

3 (28 n - 9)

Step-by-step explanation:

Simplify the following:

-9 (1 - 10 n) - 2 (3 n + 9)

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-2 (3 n + 9) = -6 n - 18:

90 n + -6 n - 18 - 9

Grouping like terms, 90 n - 6 n - 18 - 9 = (90 n - 6 n) + (-9 - 18):

(90 n - 6 n) + (-9 - 18)

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2 years ago

A circular swimming pool has a diameter of 40 meters. The depth of the pool is constant along west-east lines and increases line

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Answer:

Volume is $2000\pi\ m^{3}$

Solution:

As per the question:

Diameter, d = 40 m

Radius, r = 20 m

Now,

From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:

iff

h(y) = cy + d

Then

when y = 1 m

h(- 20) = 1 m

1 = c.(- 20) + d = - 20c + d (1)

when y = 9 m

h(20) = 9 m

9 = c.20 + d = 20c + d (2)

Adding eqn (1) and (2)

d = 5 m

Using d = 5 in eqn (2), we get:

$c = \frac{1}{5}$

Therefore,

$h(y) = \frac{1}{5}y + 5$

Now, the Volume of the pool is given by:

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A = $r\theta$

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Thus

$V = \int (\frac{1}{5}y + 5)dA$

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$V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}r^{2}sin\theta + 5r}) dr\ d\theta$

$V = \int_{0}^{2\pi} (\frac{1}{15}20^{3}sin\theta + 1000) d\theta$

$V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}$

$V = 0 + 2\pi \times 1000 = 2000\pi\ m^{3}$

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3 years ago