Answer:
9x + 1 = 9x + 1. . LISTEN BECAUSE WHWN 9X IS WITH BASE AND IN 1 THERE IS NO X IN 1. SO,WHEN THERE BASE ARE EQUAL THEN ONLY WE CAN CALCULATE IT.OR TO DO ANY EQUATION OF IT.
Answer:
ok
Step-by-step explanation:
mark me brilliant
plzzz
The intensity level is hard and for the first part, it’s 168. and something. Sorry that’s all I figured out I’m not too smart :/

2d +9= 19
The solution is d =

Hello there, first we can place our equation, which you have stated
, this algebra, in algebra we want to find the exact value of the variable, or have the variable on one side of the equation.
First we can subtract
with both sides of the equation giving us the result of
, this can also be represented as
, now just divide both sides of the equation by
, our answer is
.
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Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:

Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.