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lesantik [10]
3 years ago
15

LaToya decides to join a gym for a minimum of one month to train for a triathlon. The gym charges a beginner's fee of $100 and a

monthly fee of $38. If x represents the number of months that LaToya is a member of the gym, the equation below can be used to determine C, her total membership fee for that duration of time:
100 + 38x = C

LaToya has allocated a maximum of $404 to spend on her gym membership. Which number line shows the possible number of months that LaToya can be a member of the gym?
Mathematics
2 answers:
posledela3 years ago
4 0

Answer:

Number line with closed circle on 1 and 8, shading in between.

Step-by-step explanation:

This is the question you are referring to.

LaToya decides to join a gym for a minimum of one month to train for a triathlon. The gym charges a beginner's fee of $100 and a monthly fee of $38. If x represents the number of months that LaToya is a member of the gym, the equation below can be used to determine C, her total membership fee for that duration of time:

as 100+38x=C is our equation to determine the number of months, with $404 as a Maximum amount for her to spend, we know the beginners fee is 100 and every month(Including the first) is 38 dollars. we can understand that in 8 months, she will reach exactly 404 dollars spent on her membership.

posledela3 years ago
3 0
Well 404 dollars subtract 100 for member ship and have 304 then divide 304 divided by 38 and you get 8 months plug it in and bam 8 is c which makes sesne when checking your answer
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Cherise is tracking her heart rate during a 20-mile bike ride. In 1/3 min, her heart beats 56 times. What is Cherise’s heart rat
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2d +9= 19<br> The solution is d =
Novosadov [1.4K]

{\huge{\boxed{\mathbb{QUESTION}}}

2d +9= 19

The solution is d =

{\huge{\boxed{\mathbb{ANSWER\:WITH\:EXPLANATION}}}

Hello there, first we can place our equation, which you have stated

2d+9=19, this algebra, in algebra we want to find the exact value of the variable, or have the variable on one side of the equation.

First we can subtract 9 with both sides of the equation giving us the result of 2d=10, this can also be represented as 2\cdot d=10, now just divide both sides of the equation by 2, our answer is d=5.

_____________________

{\huge{\boxed{\mathbb{ANSWER}}}

  • {\boxed{d=5}}

_____________________

<h3><em>Have a good day :) !</em></h3>
6 0
3 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
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