Answer:
Part 1) The length of each side of square AQUA is
Part 2) The area of the shaded region is
Step-by-step explanation:
Part 1)
<em>step 1</em>
Find the radius of the circle S
The area of the circle is equal to
we have
substitute in the formula and solve for r
simplify
<em>step 2</em>
Find the length of each side of square SQUA
In the square SQUA
we have that
SQ=QU=UA=AS
Let
x------> the length side of the square
Applying the Pythagoras Theorem
Part 2) we know that
The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle
<em>Find the area of the larger circle</em>
The area of the circle is equal to
we have
substitute in the formula
step 2
Find the length of each side of square BCDE
we have that
The diagonal DB is equal to
Let
x------> the length side of the square BCDE
Applying the Pythagoras Theorem
step 3
Find the area of the square BCDE
The area of the square is
step 4
Find the area of the smaller circle
The area of the circle is equal to
we have
substitute in the formula
step 5
Find the area of the shaded region