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3 years ago

I’m being timed!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

hammer [34]3 years ago

8 0

Answer:

y=mx+b

Step-by-step explanation:

m and b can be any two real numbers.

y=mx+b

No real work, one of those linear equations that should be memorized.

WITCHER [35]3 years ago

7 0

Answer:

y=mx+b

Step-by-step explanation:

y=mx+b

If you know the slope m , and y -intercept (0,b) of a line (the point where the line crosses the y -axis), you can write the equation of the line in slope-intercept form .

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Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

4 years ago

In circle O, RV= 4 and VO= 7 find BA

Talja [164]

I think you will have t use theorem Ba=Rv^2+vo^2 Ba=4^2+7^2 Ba=16+49 Ba=65

4 0

4 years ago

AB ← → is tangent to circle O at point A. If m∠AOB = 55°, what is m∠ABO ?

AlladinOne [14]

A tangent forms a right angle with the centre of circle at the point it touches the circumference. i.e. OAB = 90 degrees
If AOB = 55 degrees, then ABO = 90 - 55 = 35 degrees

3 0

3 years ago

Read 2 more answers

Triangle ABC has the following coordinates: A (-2, 3) B (4, -3) C (-2, -3) What are the coordinates points for triangle A'B'C' i

lina2011 [118]

Answer:

A' (3/2, -9/4)

B' (-3, 9/4)

C' (3/2, 9/4)

Step-by-step explanation:

1. You have the following coordinates of the vertices of the triangle ABC:

A (-2, 3) B (4, -3) C (-2, -3)

2. The given scale factor is -3/4, therefore, to calculate the coordinates of the triangle A'B'C', you must multiply each coordinate of the triangle ABC by the scale factor.

3. Therefore, you obtain that the the coordinates of the triangle A'B'C' are:

A'=((-2)(-3/4), (3)(-3/4))=(3/2, -9/4)

B'=(4(-3/4), (-3)(-3/4))=(-3, 9/4)

C'=((-2)(-3/4), (-3)(-3/4))=(3/2, 9/4)

7 0

4 years ago

If the square of x is 5, then the square of 4x will be?<br> a) 400<br> b) 80<br> c) 60<br> d)20

Tamiku [17]

Answer:

OPTION B: 80

SEE THE IMAGE FOR SOLUTION