JK + KL = JL
JK = 2x, KL = x + 2, JL = 5x - 10
therefore we heve the equation:
2x + (x + 2) = 5x - 10
3x + 2 = 5x - 10 |-2
3x = 5x - 12 |-5x
-2x = -12 |:(-2)
x = 6
JK = 2x → JK = 2(6) = 12
KL = x + 2 → KL = 6 + 2 = 8
JL = 5x - 10 → JL = 5(6) - 10 = 30 - 10 = 20
Check:
JK + KL = JL
12 + 8 = 20 CORRECT :)
2 x 5/ 50 x 18
10 / 900
Divide both by 10
1/90
I believe that would be 64C.
Answer:
Probablity of getting six in at most three roll= 0.199.
Step-by-step explanation:
Given: Dice rolled at most 3 times untill a 6 occurs.
First, finding the probablity of getting 6 in a dice if rolled once.
Probablity= 
We know, dice have six side, therefore, total number of event will be 6.
∴ Probablity of getting six in one roll= 
As given, Dice is rolled at most 3 times.
Now, finding the probablity of getting 6 in a dice if rolled 3 times.
∴ Probablity of getting six in three roll= 
⇒ Probablity of getting six in three roll= 
Taking LCD 216
⇒Probablity of getting six in three roll= 
⇒Probablity of getting six in three roll= 
∴Probablity of getting six in three roll=0.199