Question

what is the standard form of the equation of a circle with the center 16,4 and a radius of 2 radical 2

Answer 1

Answer:

(x - 16)² + (y - 4)² = 8

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (16, 4) and r = 2$\sqrt{2}$, thus

(x - 16)² + (y - 4)² = (2$\sqrt{2}$ )², that is

(x - 16)² + (y - 4)² = 8