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artcher [175]
3 years ago
5

what is the standard form of the equation of a circle with the center 16,4 and a radius of 2 radical 2

Mathematics
1 answer:
Stella [2.4K]3 years ago
6 0

Answer:

(x - 16)² + (y - 4)² = 8

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (16, 4) and r = 2\sqrt{2}, thus

(x - 16)² + (y - 4)² = (2\sqrt{2} )², that is

(x - 16)² + (y - 4)² = 8

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