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3 years ago

Determine the solution set of (x - 4)2 = 12

Mathematics

1 answer:

Travka [436]3 years ago

4 0

Answer:

Step-by-step explanation:

(x - 4) × 2 = 12

x - 4 = 12 ÷ 2

x - 4 = 6

x = 10

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Y=2x+3 4x+y=33 substitution form (x, y)

galina1969 [7]

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4 years ago

Is the equation true, false, or open? 9p+8=10p+7

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3 years ago

It is know that BD is an angle bisector with...

Georgia [21]

Answer: x = 10 or x = -6

Step-by-step explanation: If ray BD bisects <ABC, then <ABD ≅ <DBC.

So we can setup the equation x² - 4x = 60.

To solve this polynomial equation, we need to set it equal to 0.

So we subtract 60 from both sides to get x² - 4x - 60 = 0.

On the left, we have a trinomial in a special form that can

be factored as the product of two binomials.

In the first position of each binomial,

we have the factors of the x squared term, x and x.

In the second position, we're looking for the factors

of -60 that add to -4 which are -10 and +6.

So we have (x - 10)(x + 6) = 0.

Whenever two terms are multiplied together to equal 0,

this means that either one or the other must equal 0.

So if (x - 10)(x + 6) = 0, then either x - 10 = 0 or x + 6 = 0.

Solving each equation from here, we find that x = 10 or x = -6.

If you plug both values of x in for the measures of the angles,

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3 0

3 years ago

2. The ratio of radii of two cylinders is 1:2 and heights are in the ratio 2:3. Find the ratio of their volumes.

Savatey [412]

Answer: $\frac{1}{6}$ or $1:6$

Step-by-step explanation:

The volume of a cylinder can be found with the following formula:

$V=\pi r^2h$

Where "r" is the radius and "h" is the height of the cylinder.

In this case, let be:

- $V_1$ the volume of one of this cylinders and $V_2$ the volume of the other one.

- $r_1$ the radius of the first one and $r_2$ the radius of the other cylinder.

- $h_1$ the height of one of them and $h_2$ the height of the other cylinder.

Then:

$V_1=\pi r_1^2h_1\\\\V_2=\pi r_2^2h_2$

Therefore, you know this:

$\frac{V_1}{V_2} =\frac{\pi r_1^2h_1}{\pi r_2^2h_2}$

Simplifying, you get:

$\frac{V_1}{V_2} =\frac{ r_1^2h_1}{ r_2^2h_2}$

Now, knowing the ratios given in the exercise, you can substitute them into the equation:

$\frac{V_1}{V_2} =\frac{1^2*2}{ 2^2*3}$

Evaluating, you get:

$\frac{V_1}{V_2} =\frac{2}{ 4*3}\\\\\frac{V_1}{V_2} =\frac{2}{12}\\\\\frac{V_1}{V_2} =\frac{1}{6}$

4 0

4 years ago

2x2 + 3x + 1 = 0 A= b = C=

egoroff_w [7]

Answer:

ax2+bx+c

Step-by-step explanation:

A-2

B-3

C-1

7 0

3 years ago

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