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2 years ago

Determine the solution set of (x - 4)2 = 12

Mathematics

1 answer:

Travka [436]2 years ago

4 0

Answer:

Step-by-step explanation:

(x - 4) × 2 = 12

x - 4 = 12 ÷ 2

x - 4 = 6

x = 10

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To increase, use 1.3

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Step-by-step explanation

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2 years ago

Determine if the set is a Pythagorean triple

balandron [24]

Answer:

Pythagorean Triples are sets of whole numbers for which the Pythagorean Theorem holds true. The most well-known triple is 3, 4, 5. This means that 3 and 4 are the lengths of the legs and 5 is the hypotenuse.

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2 years ago

In ΔABC, if m ∠A = m∠C, m∠B = ß (where ß is an acute angle), and BC = x, which expression gives the length of b, the side opposi

chubhunter [2.5K]

Answer:

The length of b is $\sqrt{2x^2(1-cos\beta)}$ .

Step by step explanation:

Given information: In ΔABC, ∠A =∠C, ∠B = ß (where ß is an acute angle), and BC = x.

Since two angles are same therefore triangle ABC is an isosceles triangle and side AB and BC are congruent.

$AB=BC=x$

According to Law of cosine

$b^2=a^2+c^2-2ac\cos B$

$b^2=x^2+x^2-2(x)(x)\cos \beta$

$b^2=2x^2-2x^2\cos \beta$

$b^2=2x^2(1-\cos \beta)$

$\sqrt{2x^2(1-cos\beta)}$

Therefore the length of b is $\sqrt{2x^2(1-cos\beta)}$ .

6 0

2 years ago

PLEASE HELP ME!!!!!!!!

Delicious77 [7]

Angle θ between two vectors is given by, $\theta =cos^{-1}( \frac{u
 \cdot v}{|u||v|} )$ ; where $u \cdot 
v=-5(-4)+(-4)(-3)=20+12=32$ ; $|u|= \sqrt{ (-5)^{2} + (-4)^{2} } = 
\sqrt{25+16} = \sqrt{41}$ and $|v|=\sqrt{ (-4)^{2} + (-3)^{2} } = 
\sqrt{16+9} = \sqrt{25}=5$ .
Therefore, $\theta =cos^{-1}( \frac{32}{ 5\sqrt{41}} )=cos^{-1}0.9995=1.8^o$

3 0

3 years ago

PLEASE HELP FAST!!!!!!!!!!!!!!!!!!!!!! Which two numbers on the number line have an absolute value of 1?

Alisiya [41]

Answer:

Step-by-step explanation:

-1 and 1.

They are both 1 away from 0, meaning that the absolute value of both are 1.

7 0

2 years ago