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pishuonlain [190]
2 years ago
6

Write the equation of the line that passes through (2,-4) and (-1,-1)

Mathematics
2 answers:
algol132 years ago
5 0
You need to use the y = mx + b formula which will get you to the answer
y = -x -2
galben [10]2 years ago
5 0

Answer:

y = - x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, - 4) and (x₂, y₂ ) = (- 1, - 1)

m = \frac{-1+4}{-1-2} = \frac{3}{-3} = - 1 , thus

y = - x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 1, - 1 ), then

- 1 = 1 + c ⇒ c = - 1 - 1 = - 2

y = - x - 2 ← equation of line

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What is the standard deviation of the following data set rounded to the nearest tenth? 56 ,78 ,123 , 34, 67, 91, 20
quester [9]

Answer:

The standard deviation of the following data set is 32.2

Step-by-step explanation:

step 1

Find the mean

we have

[56,78,123,34,67,9,20]

Sum the data and divided by the number of elements

[56+78+123+34+67+91+20]/7=469/7=67

step 2

For each number: subtract the Mean and square the result

[(56-67)^{2},(78-67)^{2},(123-67)^{2},(34-67)^{2},(67-67)^{2},(91-67)^{2},(20-67)^{2}]

[121,121,3,136,1,089,0,576,2,209]

step 3

Work out the mean of those squared differences

[121+121+3,136+1,089+0+576+2,209]/7=1,036

This value is called the "Variance"    

step 4

Take the square root of the variance

standard\ deviation=\sqrt{1,036}=32.2

6 0
3 years ago
How do you simply the square root of 28
maria [59]
\sqrt{28} can be rewritten as ;
=\sqrt{7*4}
=\sqrt{4} * \sqrt{7}
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3 years ago
NEED HELP!!!<br> it'll be helpful if someone could help out with these questions.
gayaneshka [121]

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Step-by-step explanation:

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JulsSmile [24]

Answer:

8

Step-by-step explanation:

There is no number line given, so I will use the "keep change flip" method.

\frac{2}{3}\div\frac{1}{2}\\\rule{150}{0.5}\\  \frac{2}{3}\cdot\frac{12}{1}\\\\\frac{2\cdot12}{3\cdot1}\\\\\frac{24}{3}\\\\\boxed{8}

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