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suter [353]
2 years ago
10

What equation represents the relationship between p and q shown in the table

Mathematics
1 answer:
mash [69]2 years ago
6 0

q = 10p because all of them are multiplied by ten

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Seee the attachment photo plz<br><br>​
Ray Of Light [21]

Answer:

not sure

Step-by-step explanation:

7 0
2 years ago
the 43rd term of an arithmetic sequence is -671 and the 52nd term is -806. find the first term and the common difference.
Bond [772]

Answer:

First term = -41.

Common difference = -15.

Step-by-step explanation:

nth term: an = a1 + (n - 1)d  where a = first term and d = the common difference.

-671 = a1 + (43 - 1)d

-806 = a1 +(52 - 1)d

-671  = a1 + 42d

-806 = a1 + 51d

Subtracting ( to eliminate a1):

-671 - (-806) = 42d - 51d

-9d =  135

d = -15

Substitute for d in the first equation:

-671 = a1 + 42*-15

-671 = a1 - 630

a1 = -671 + 630 = -41.

3 0
2 years ago
A line has a slope of 7 and contains the point (5, −9).
sergejj [24]
Your answer would come out to be y=7x-44 
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Those match up to that answer.
7 0
3 years ago
Sydney applied the steps below to find the product of (3.1)(–1.6).
postnew [5]

 to get the numbers in step 3

multiply -1.6 by 3

then multiply -1.6 by 0.1

 and add them together

answer is D) (–1.6)(3) + (–1.6)(0.1)

7 0
3 years ago
Read 2 more answers
Anyone for 10 points??!!!<br> The question is in the image<br> Thanks But answer ASAP!
ivanzaharov [21]
Bottom Side Surface Area:

(24 inches + 24 inches + 24 inches) * (30 inches)

= 72 inches * 30 inches

= 2160 inches squared


--------

Top Side Surface Area:

24 inches * 30 inches

= 720 inches squared

--------

Length of the diagonal (D) which needs to be measured:

*Use Pythaogras's theorem...

24^2 + 10^2 = D^2

D=√(24^2+10^2)

D=26 inches

------------

Measure the surface area of the two ramps:

26 inches * 30 inches * 2

= 1560 inches squared

-----------

Total surface area:

2160 inches squared + 720 inches squared + 1560 inches squared

= 4440 inches squared

---------

Answer:

4440 square inches
8 0
3 years ago
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