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Soloha48 [4]
3 years ago
8

Solve for x. 5+x+(−2)=−8

Mathematics
2 answers:
lord [1]3 years ago
7 0
This is simple, move the numbers to the other side and change the signs when doing so, x = -8 - 5 - 2 which gives you x = -15
Feliz [49]3 years ago
6 0
5+x+(−2)=−8
Simplify
5 + x - 2 = -8
x + 3 = -8
Subtract 3 to both sides
x + 3 - 3 = -8 +3
Simplify
x = -5

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-9=-3(x+2)<br>solve for x <br>show steps
lianna [129]

SimplifyOkie dokie so first things first, you have to get rid of those parentheses! To do this you use the distributive property. -3(x+2) is the same thing as -3(x)+-3(2). that and you get -9=-3x-6. So you want to get x by itself to be able to find what x is, so you add 6 to both sides of the equation to get rid of the -6. So then you get -3=-3x. Then you must divide both sides by the coefficient of x, which would be -3. When you divide both sides by -3 you get -3/-3=x, which is the same thing as 1=x. Hope this helped!

4 0
4 years ago
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When you double my number and add five you get 17 what is my number
Alexeev081 [22]

the answer is 6, 6 times 2 is 12 plus 5 is 17

3 0
3 years ago
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Find the value of x! Justify your answer!
Daniel [21]

Answer:

Use the Triangle exterior angle theorem. The definition of this theorem, is that the exterior angle you are solving for is the sum of the two opposite interior angles. Set the equation:

80 + x = 3x - 22

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract x and add 22 to both sides.

80 (+22) + x (-x) = 3x (-x) - 22 (+22)

80 + 22 = 3x - x

Simplify.

102 = 2x

Isolate the variable, x. Divide 2 from both sides.

(102)/2 = (2x)/2

x = 102/2

x = 51

Check. Plug in 51 to the equation given.

80 + x = 3x - 22

80 + (51) = 3(51) - 22

131 = 153 - 22

131 = 131 (True).

~

7 0
4 years ago
Find a solution to the initial value problem, y′′+18x=0,y(0)=5,y′(0)=1.
Serga [27]

We want to find a solution to the initial value problem:

y'' + 18x = 0 \qquad,\qquad y(0) = 5 \qquad,\qquad y'(0)=1.

We can start by integrating the equation once:

\dfrac{\textrm{d}^2 y}{\textrm{d}x^2} + 18 x = 0 \iff \dfrac{\textrm{d}^2 y}{\textrm{d}x^2} = -18 x \iff\\\\\iff \dfrac{\textrm{d}y}{\textrm{d}x} = -18\displaystyle\int x\textrm{ d}x \iff \dfrac{\textrm{d}y}{\textrm{d}x}=-18\dfrac{x^2}{2} + C \iff\\\\\iff \dfrac{\textrm{d}y}{\textrm{d}x} = -9x^2 + C.

Using the initial condition y'(0) = 1, we can determine the integration constant C:

\dfrac{\textrm{d}y}{\textrm{d}x}\Big\vert_{x= 0} = 1 \iff -9 \times 0^2 + C = 1 \iff C = 1.

Therefore, we have:

\dfrac{\textrm{d}y}{\textrm{d}x} = -9x^2 + 1

We can now integrate again:

y(x) = \displaystyle\int\dfrac{\textrm{d}y}{\textrm{d}x}\textrm{ d}x = \int\left(-9x^2+1\right)\textrm{d}x = -9\int x^2\textrm{ d}x + \int\textrm{d}x =\\\\= -9\dfrac{x^3}{3} + x + K = -3x^3 + x + K.

The integration constant K is determined by using y(0) = 5:

y(0) = 5 \iff -3 \times 0^3 + 0 + K = 5 \iff K = 5.

Finally, the solution is:

\boxed{y(x) = -3x^3 + x + 5}.

7 0
3 years ago
Line A <br> Line B<br> Or Line C<br> Or D?<br> Thanks to whoever helps (:
vova2212 [387]
Answer is B. It isn't going up or down on the y axis
8 0
4 years ago
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