Question

16. How many liters of a 60% alcohol solution must be added to 60 liters of a 30% alcohol

Answer 1

Step-by-step explanation:

Step 1: Question statement and Inferences

Let x liters of the 60% solution be added.

So, amount of Alcohol in this solution = 60% of x = 0.6x L

Now, let us consider the 40% solution.

The total volume of this solution is 50 L

So, amount of Alcohol in this solution = 40% of 50

 

Step 2: Finding required values

When x L of 60% solution are mixed with 50 L of the 40% solution, the total volume of the resultant solution will be (50+x) L

By the Law of Conservation of Mass,

Amount of alcohol in the input solutions = Amount of alcohol in the final solution

=> Amount of alcohol in the final solution = 20 + 0.6x

So, concentration of Alcohol in the final solution



Step 3: Calculating the final answer

It is given that the concentration of alcohol in the final solution is 50%



Answer 2

Agreed with guy above thanks