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algol13
3 years ago
13

16. How many liters of a 60% alcohol solution must be added to 60 liters of a 30% alcohol

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
8 0

Step-by-step explanation:

Step 1: Question statement and Inferences

Let x liters of the 60% solution be added.

So, amount of Alcohol in this solution = 60% of x = 0.6x L

Now, let us consider the 40% solution.

The total volume of this solution is 50 L

So, amount of Alcohol in this solution = 40% of 50

 

Step 2: Finding required values

When x L of 60% solution are mixed with 50 L of the 40% solution, the total volume of the resultant solution will be (50+x) L

By the Law of Conservation of Mass,

Amount of alcohol in the input solutions = Amount of alcohol in the final solution

=> Amount of alcohol in the final solution = 20 + 0.6x

So, concentration of Alcohol in the final solution



Step 3: Calculating the final answer

It is given that the concentration of alcohol in the final solution is 50%



enyata [817]3 years ago
8 0
Agreed with guy above thanks
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Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

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