A standard deck has 52 cards.
A standard deck has 4 jacks.
A standard deck has 13 clubs.
From this, we can derive the following:
The probability of drawing a jack is 4/52 or 1/13
The probability of drawing a club is 13/52 or 1/4
But since the problem asks for drawing jack or club, therefore we should add the 2 probabilities, making 17/52. This is not the final answer yet. We know that there is a jack of clubs, therefore we need to subtract 1 from the probabilities since jack of clubs were considered in the 2 categories of probability.
With that being said, the probability of drawing a club or a jack is 16/52 or 4/13
Bonus Question:
The first thing you need to do here is find the probability of each scenario. First let's do what is given, the probability of drawing 2 aces. Since there are 4 aces in a deck of 52, we can easily say that the probability of drawing an ace is 4/52. However for our second draw, the probability of drawing a different ace is 3/51. This is so since we already drew a card that is an ace, hence we need to subtract one from the total aces (4-1) and from the total cards in the deck (52-1). In getting the probability of drawing two aces, we need to multiply the said probabilities: 4/52 and 3/51, resulting to 1/221.
For the second scenario, the drawing of 2 red cards, we just use the same concept but in this, we are already considering the 2 red cards in the first scenario, therefore the chance of drawing a red on our first draw is 24/52. For our second, we just need to subtract one card, therefore 23/51. Multiply these two and we will get 46/221.
Now, the problem asks for the chance of drawing either 2 reds or 2 aces, therefore we add the probabilities of the 2 scenarios:
46/222 + 1/221 = 47/221
Summary:
First Scenario:
4/52 + 3/51 = 1/221
Second Scenario:
24/52 + 23/51 = 46/221
Chances of drawing 2 red cards or 2 aces:
1/221 + 46/221 = 47/221
13 x 13
or
13^2 (13²) will give you 169
and when two negative numbers are put together you get a positive so in this case -13 would work too.
If you were to solve this equation with fractions with the same denominater, you only need to pay attention to the numerater.
you have 8/5 liters to fill 1/5 containers, 8 goes in to 1 8 times, therefore you can fill the cup eight times.
The answer is 8
idk mabye try to add or mulipacation.... wait oh well im in the 3rd grade soooooo mabye = or + - 90.63/100=0.9o63 i thiink its 0 :)
Answer:
They are 24, 692 feet aprart
Step-by-step explanation:
Let us assume at the instance we are measuring their position, that Pluto is at the highest point in the air, which is = 24,568 feet, and Goofy is at the lowest point of the sea (that he can go) = 124 feet.
Before we can proceed with the addition, we need to establish a datum, which will serve as the reference point from which the two distances are measured. This definitely is the sea level, because altitude and depth are usually measured above and below sea level.
Pluto's location to the sea level = 24,568 feet
Goofy's Location to the sea level = 124 feet
their distance apart = 24,568 feet + 124 feet =24, 692 feet apart
