Angle 2=3, so angle 1=4 because angles ABC & BCD equal 90°. When you add together the angles of a triangle you get 180 and if you could put angle 1 and 4 together it would look like an upward version.
That is the best way I could describe it. Hope that helps.
<h3>
<u>Answer:</u></h3>
<h3>
<u>Step-by-step explanation:</u></h3>
Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.
From the figure it's clear that the area of shaded region will be the difference of areas of two circles.
Let the,
- Radius of smaller circle be r .
- Radius of smaller circle be r .
- Area of shaded region be
![\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}](https://tex.z-dn.net/?f=%5Cbf%20%5Cimplies%20Area_%7BShaded%7D%3D%20Area_%7Bbigger%7D-Area_%7Bsmaller%7D%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7BShaded%7D%20%3D%20%5Cpi%20R%5E2%20-%20%5Cpi%20r%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%3D%20%5Cpi%20%28%20R%5E2-r%5E2%29%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%3D%20%5Cpi%20%5B%20%2810cm%29%5E2%20-%20%284cm%29%5E2%5D%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cpi%20%5B%20100cm%5E2-16cm%5E2%5D%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cpi%20%5Ctimes%2084cm%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cdfrac%7B22%7D%7B7%7D%5Ctimes%2084cm%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20%5Cboxed%7B%5Cred%7B%5Cbf%20Area_%7Bshaded%7D%20%3D%20264%20cm%5E2%20%7D%7D)
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<u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>
- cos ( 1/2 x + 1/5 π ) = 0 ( and because if cos α = 0, α= π/2 + k π, k ∈ Z )
1/2 x + π/5 = π/2 + k π, k ∈ Z
1/2 x = π/2 - π/5 + k π / * 2
x = π - 2π/5 + 2 k π
x = 3/5 π + 2 k π = 0.6 π + 2 k π
Answer:
If k = 0: x 1 = 0.6 π = 3π/5
k = 1 : x 2 = 2.6 π = 13π/5
Answer:
about 9.4 units
Step-by-step explanation:
Distance formula:
√(x1 - x2)² + (y2 - y1)²
Coordinates:
A (4, 2)
B (9, 10)
Let's make 9 = x1
Let's make 4 = x2
Let's make 10 = y1
Let's make 2 = y2
Substitute into the distance formula:
√(x1 - x2)² + (y2 - y1)²
√(9 - 4)² + (2 - 10)²
Solve:
√(9 - 4)² + (2 - 10)²
√(5)² + (-8)²
√25 + 64
√89
≈ 9.4
Therefore, the length of AB is approximately 9.4 units.
The is number 3 or c. I hope this helps.
