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Setler [38]
3 years ago
14

How to download gta5 ​

Computers and Technology
2 answers:
Kazeer [188]3 years ago
8 0
Buy the game and hit download
Lostsunrise [7]3 years ago
8 0
By adding me on Instagram bruh bruh bruh
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A hard disk has four surfaces (that's top and bottom of two platters). Each track has 2,048 sectors and there are 131,072 (217)
marysya [2.9K]

Answer:

128 GB

Explanation:

Here, we are interested in calculating the total capacity of the disk.

From the question, we can identify the following;

Number of surfaces = 4

Tracks per surface = 131,072

Number of sectors = 2,048

Each Block size = 512 bytes

Mathematically;

Total data capacity of the disk = no of tracks * no of sectors * block size

= 131,072 * 2048 * 512 bytes

= 2^17 * 2^11 * 2^9 bytes = 2^37 bytes

1 GB = 2^30 bytes

So 2^37 = 2^7 * 2^30

= 128 GB

8 0
3 years ago
If you were an online community director, you might use both chat and e-mail in your community. What are some similarities and d
stealth61 [152]

Emails are formal

Online chats are private and friendly

Emails are used for business

Online chats are for friends

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3 years ago
Write the pseudocode for the following:
Marta_Voda [28]
Answer: A


Explanation:
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4 years ago
What does the clone tile command do?
Angelina_Jolie [31]
It allows you to create tiled copies of an object while tweaking the variables
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3 years ago
Read 2 more answers
Given two complex numbers, find the sum of the complex numbers using operator overloading.Write an operator overloading function
Inessa05 [86]

Answer:

I am writing the program in C++ programming language.  

#include<iostream>  // to use input output functions

using namespace std;   // to identify objects like cin cout

class ProblemSolution {  //class name

private:  

// private data members that only be accessed within ProblemSolution class

int real, imag;

 // private variables for real and imaginary part of complex numbers

public:  

// constructor ProblemSolution() to initialize values of real and imaginary numbers to 0. r is for real part and i for imaginary part of complex number

ProblemSolution(int r = 0, int i =0) {  

real = r; imag = i; }  

/* print() method that displays real and imaginary part in output of the sum of complex numbers */

void print(){  

//prints real and imaginary part of complex number with a space between //them

cout<<real<<" "<<imag;}  

// computes the sum of complex numbers using operator overloading

ProblemSolution operator + (ProblemSolution const &P){  //pass by ref

          ProblemSolution sum;  // object of ProblemSolution

          sum.real = real + P.real;  // adds the real part of the  complex nos.

          sum.imag = imag + P.imag;  //adds imaginary parts of  complex nos.

//returns the resulting object

          return sum;       }  //returns the sum of complex numbers

};   //end of the class ProblemSolution

int main(){    //start of the main() function body

int real,imag;  //declare variables for real and imaginary part of complex nos

//reads values of real and imaginary part of first input complex no.1

cin>>real>>imag;  

//creates object problemSolution1 for first complex number

ProblemSolution problemSolution1(real, imag);  //creates object

//reads values of real and imaginary part of first input complex no.2

cin>>real>>imag;

//creates object problemSolution2 for second complex number

ProblemSolution problemSolution2(real,imag);

//creates object problemSolution2 to store the addition of two complex nos.

ProblemSolution problemSolution3 = problemSolution1 + problemSolution2;

problemSolution3.print();} //calls print() method to display the result of the //sum with real and imaginary part of the sum displayed with a space

Explanation:

The program is well explained in the comments mentioned with each statement of the program. The program has a class named ProblemSolution which has two data members real and imag to hold the values for the real and imaginary parts of the complex number. A default constructor ProblemSolution() which initializes an the objects for complex numbers 1 and 2 automatically when they are created.

ProblemSolution operator + (ProblemSolution const &P) is the operator overloading function. This performs the overloading of a binary operator + operating on two operands. This is used here to add two complex numbers.  In order to use a binary operator one of the operands should be passed as argument to the operator function. Here one argument const &P is passed. This is call by reference. Object sum is created to add the two complex numbers with real and imaginary parts and then the resulting object which is the sum of these two complex numbers is returned.  

In the main() method, three objects of type ProblemSolution are created and user is prompted to enter real and imaginary parts for two complex numbers. These are stored in objects problemSolution1 and problemSolution2.  Then statement ProblemSolution problemSolution3 = problemSolution1 + problemSolution2;  creates another object problemSolution3 to hold the result of the addition. When this statement is executed it invokes the operator function ProblemSolution operator + (ProblemSolution const &P). This function returns the resultant complex number (object) to main() function and print() function is called which is used to display the output of the addition.

4 0
4 years ago
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