The answer would be: Go on a vacation that costs $3,500
Paying off money for buying a car will not decrease your net worth as you get the car as assets for the money you use. But the depreciates 20% will cause you to lose $3,000 assets. Assuming you are not buying assets at all, go on a vacation that costs $3,500 will increase liability without any effect on assets. Paying up bills will decrease your asset but it also decreases your liability so the net worth wouldn't change.
Answer:
Hi there! The question is checking your knowledge on Pseudocode. Pseudocode is a high level solution written in plain English to outline the steps needed for the program to work correctly. An implementation for the different parts of the question is written below.
Explanation:
1. Determine the area of a triangle
declare formula for area calculation of triangle as ½ * (base * height)
validate input parameters “base” and “height”
apply formula and return result
2. Compute the interest earned Prompt user for input 2
declare formula for interest calculation as annual interest rate * term * starting account balance
validate input parameters “interest_rate” and “starting_account_balance ”
apply formula and return result as final balance at the end of the year as the interest earned + starting balance.
3. Determine the flying time between two cities given the mileage M between them and the average speed of the airplane.
declare formula for time calculation of triangle as time = distance / speed
validate input parameters for mileage “M” and speed “S”
apply formula and return result
Answer: Rich medium
Explanation: A communication is said to be rich id it provides the services like observing the body language, immediate communication, instant judging of the voice tone etc. These factors are commonly found in the face to face interaction which is considered as the rich source of communication. It is considered as rich medium because it has the capability of receiving the output immediately .
Answer:
void print2(int row) {
for (int i = 0; i < row; i++) {
char ch = 'a';
char print = ch;
for (int j = 0; j <= i; j++) {
cout << print++;
}
cout << endl;
}
}
int count_digits(int num) {
int count = 0;
int temp = num;
while (temp != 0) {
temp = temp / 10;
count++;
}
return (num % count);
}
Explanation:
