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Elanso [62]
3 years ago
12

You have $1.55 worth of dimes and nickels in a jar. There are 23 coins in the jar. How many dimes do you have? How many nickels

do you have
Mathematics
1 answer:
Scilla [17]3 years ago
3 0

i believe the answer is 35 dimes and 65 nickels (sorry if i’m wrong lol)

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describe how to transform (^5 square root x^7)^3 into an expression with a rational exponent. make sure you respond with complet
diamong [38]

Answer:

x^\frac{21}{5}

Step-by-step explanation:

We are given an expression and we have to transform it into an expression with exponent.

5th root of x can be written as x^\frac{1}{5}

(\sqrt[5]{x^7})^3\\\\((x^7)^\frac{1}{5} )^3


The powers outside will be multiplied as: (x^a)^b = x^{ab}

(x^\frac{7}{5} )^3\\x^\frac{7*3}{5}\\x^\frac{21}{5}


where the exponent is \frac{21}{5} and it is a rational number by definition of rational numbers

3 0
3 years ago
I’m doing homework corrections can someone help me with this one
salantis [7]

between 50 and 100 it has 5 lines. so, 100-50 = 50 and divide to 5. because there are 5 parts. 50/5 = 10.1 line = 10. 50 + 10 + 10 = 70.ans: 70

4 0
3 years ago
Which answer is correct!?!?
Naya [18.7K]
46%d+57%y=55%x42
x+y=42

Find y

x=42-y

46%(42-y)+57%y=23.1
19.31-46%y+57%y=23.1
11%y=23.1-19.31
11%y=3.79
y=34

The answer is D
6 0
3 years ago
2•(3 (5+2) - 1) Geometry Math.​
bagirrra123 [75]

Answer:

40

Step-by-step explanation:

2 • (3(5 + 2) - 1) =

Start with the innermost parentheses.

= 2 • (3(7) - 1)

Now do the multiplication inside the parentheses.

= 2 • (21 - 1)

Do the subtraction inside the parentheses.

= 2 • 20

= 40

3 0
3 years ago
2. Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, o
Brut [27]

Hello!

To solve algebraic equations, we need to use SADMEP. SADMEP is an acronym used only solve for x in algebraic equations. SADMEP is expanded to be: subtraction, addition, division, multiplication, exponents, and parentheses.

(a) 4 + 2(-1) = 10 + 2 (multiply)

4 + -2 = 10 + 2 (add)

2 = 12

This equation has no solutions because <u>2 is never equal to 12</u>.

(b) 30 = 10 - (6 + 10) (simplify the parentheses)

30 = 10 + -1(16) (multiply)

30 = 10 - 16 (simplify)

30 = -6

This equation has no solutions because<u> 30 and -6 is never equal to each other</u>.

(c) 8x = 4x + 4x + 10(x - x)

8x = 4x + 4x + 10(x - x) (simplify [add and subtract])

8x = 8x + 10(0) (multiply)

8x = 8x  

This equation has an infinite number of solutions because if you <u>substitute any value into the original equation</u>, <u>both sides of the equation</u> will be <u>always equal</u>.

7 0
3 years ago
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