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2 years ago

A system of equations is shown below:

1 answer:

6 0

X+y=3

Subtract x from both sides

y=-x+3

Substitute

2x--x+3=6
2x+x+3=6
3x+3=6

Subtract 3 from both sides

3x=3

Divide both sides by 3

x=1

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Pl hell any thing is appreciated I will give Brainly

Zarrin [17]

Answer:

First one and last one

Step-by-step explanation:

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3 years ago

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How do u get this?? I know the answer but then I don't know why they shuld divide by 2 I will mark the person who explains wit p

Greeley [361]

Answer:

10.89

Step-by-step explanation:

Circle:

C = TTD

C = TT(6.6)

C = 20.73451151

C = 20.73

Triangle:

A = bh/2

A = 6.6(3.3)/2 6.6/2=3.3

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A = 10.89

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2 years ago

HELPPP PLEASE WILL NAME BRAINLIEST

laila [671]

The first reaction represented is a decomposition reaction due to the fact the bonded pair are being split apart.

The second equation is a single displacement because the B and C have switched places, which is the only change making it a single displacement. If there had been another bond and A had also moved, it would be double.

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3 years ago

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SpyIntel [72]

Y=3x-5

Y=5/4x+3/4

The solution to the equations is in the picture

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2 years ago

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream. What is the rate of

nikitadnepr [17]

<h3>Rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr</h3><h3><u>Solution:</u></h3>

Given that,

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream

Therefore,

Upstream distance = 165 km

Upstream time = 3 hours

<h3><u>Find upstream speed:</u></h3>

$speed = \frac{distance}{time}\\\\speed = \frac{165}{3}\\\\speed = 55$

Thus upstream speed is 55 km per hour

Downstream distance = 510 km

Downstream time = 6 hours

<h3><u>Find downstream speed:</u></h3>

$speed = \frac{510}{6}\\\\speed = 85$

Thus downstream speed is 85 km per hour

<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then</u></em>

Speed downstream = u + v km/hr

Speed upstream = u - v km/hr

Therefore,

u + v = 85 ----- eqn 1

u - v = 55 ----- eqn 2

Solve both

Add them

u + v + u - v = 85 + 55

2u = 140

u = 70

<em><u>Substitute u = 70 in eqn 1</u></em>

70 + v = 85

v = 85 - 70

v = 15

Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr

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3 years ago