Answer:
AB+BE+EF+GF+HG+AH = 14 #EQU 1
BC+CD+DE+EF+GF+BG = 22 #EQU 2
AB+BC+CD+DE+EF+GF+HG+AH = 24 #EQU 3
IMPLEMENTING EQU 2 IN EQU 3
AB+22-EF+ HG+AH = 24 # EQU 5
FROM EQU 1
AB+HG+AH = 14-(BE+EF+GF) #EQU 4
IMPLEMENTING EQU 4 IN EQU 5
22+14 - (BE+EF+GF+EF) = 24
36 - 24 = BE+EF+GF+BG(EF=BG)
12 = PATH TAKEN ON THURSDAY
Answer:
x = 65 , y = 64
Step-by-step explanation:
y - 16 and 2y + 4 are same- side interior angles and sum to 180° , that is
y - 16 + 2y + 4 = 180
3y - 12 = 180 ( add 12 to both sides )
3y = 192 ( divide both sides by 3 )
y = 64
then
2y + 4 = 2(64) + 4 = 128 + 4 = 132
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
2y + 4 is an exterior angle of the triangle , then
x + 67 = 132 ( subtract 67 from both sides )
x = 65
The answer is 24d^2-62d+35
8x -5+2 x
8x+2x-5 ( combine like terms)
answer:
10x-5 or -5+10x
Let
x-------------> amount added <span>to each side
</span>A-------------> area increased----------> 84 ft²
we know that
A=(10+x)*(5+x)=84-----------> 10*5+10*x+5*x+x²
50+15x+x²=84----------> x²+15x-34=0
<span>solving the second order equation
</span>x1=-17
x2=2
the answer is x=2 ft
