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3 years ago

8

What best describes stem cells

2 answers:

denis23 [38]3 years ago

7 0

A stem cell is a cell that has layers of bacteria that helps protect the water that follows through it.

Trava [24]3 years ago

3 0

A stem cell is a cell that has layers of bacteria that helps protect the water that flows through it . Hope this help you

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Would rain be a abiotic factor or a biotic factor?

vodomira [7]

It is an abiotic factor.

An abiotic factor is something that will never be alive.

Ex. Dirt, clouds, air.

I hope this helped you!

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4 years ago

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Plz help me with these

Digiron [165]

The controlis the plant with just water. The independent variable is the plants. The dependaent is the amout of salt in the water.

The indepedent is the trees. The dependent is the greenhouse or no greenhouse.

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3 years ago

What can be learned from using sonar in an ocean environment

Jet001 [13]

Using sonar in an ocean environment, you can determine how far below you are from reaching the bottom, or if something bigger picks up, say a whale, which in turns lets you know something big is beneath you. It helps determine how far you are under the water as well.

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3 years ago

2.86 A ball is dropped from rest from the top of a cliff that is 24 m high. From ground level, a second ball is thrown straight

Rashid [163]

Answer:

Distance Below the top = 6,02 m

Explanation:

To get the Final velocity of the first ball (that will be the intial velocity of the second) you need to solve the kinematic equation for Velocity:

(1) $V_{1f} =V_{1O} - gt$

As the ball is dropped from rest $V_{1O} = 0$ , so:

(2) $V_{1f} = - gt$

Note that the velocity is going to be negative as the ball is going down. To get the time it would take the ball to reach de base you can use the kinematic equation for position:

(3) $h_{1} = h_{1O} + V_{1O} *t - \frac{1}{2} gt^{2}$

We need the answer when h=0, and from the initial conditions $V_{1O} = 0, h_{1O} = 24m$ , you get:

(4) $24m = \frac{1}{2} gt_{1f}^{2}$

Solving for t, with $9,8\frac{m}{s^{2}}$ and :

(5) $t_{1f} = \sqrt{\frac{24m*2}{g} } = 2,21 s$

Replacing this time in (2), the final velocity is:

(6) $V_{1f} = -21,66 \frac{m}{s}$

So the initial velocity of ball 2 is equial to this but oppossite in direction so: $V_{2O}= -V_{1f} = 21,66 \frac{m}{s}$

The general position equation for ball 2 is (considering $h_{2O} = 0$ :

(7) $h_{2} = V_{2O} *t - \frac{1}{2} gt^{2}$

They cross paths when $h_{1}=h_{2}$ so:

(8) $h_{1O} - \frac{1}{2} gt^{2} = V_{2O} *t - \frac{1}{2} gt^{2}$

Rearranging:

(9) $t_{cross} =\frac{h_{1O}}{V_{2O} }$

Replacing values:

$t_{cross} = 1,108 s$

To get the absolute position replace $t_{cross}$ on equation (3) or (7):

$h_{cross} = 17,98 m$

To get it below the top of te cliff:

$h_{cross, from above} = 24 m - 17,98 m$

$h_{cross, from above} = 6,02 m$

3 0

4 years ago

Small structures inside cells that perform specific functions are called:

frosja888 [35]

Answer:

B. Organelles

Explanation:

they are called

6 0

3 years ago

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