<span>Two of the nitrogenous bases present in DNA (Guanine and Adenine) contain two rings and thus are much larger than the other two (Cytosine and Thymine), which have only one.
Nitrogenous bases with two rings (such as G and A) are known as PURINES, whereas nitrogenous bases with a single ring (such as C and T) are known as PYRIMIDINES.
A stable DNA structure is formed ONLY when the two strands are a constant distance
apart which ONLY happens when a PURINE (G or A) on one strand is paired with a PYRIMIDINE (C or T) on the other strand. The strands would have to move much further apart to permit a purine to pair with another purine and would have to move much closer together to permit a pyrimidine to pair with a pyrimidine.
(Source: https://www.amherst.edu/system/files/media/1536/ModGen_1C_TP.pdf )</span>
Answer:
In a scenario in which I have to synthesize a cell and decide why I have to pick one from Prokaryotic or eukaryotic because of their differences in the speed of the process. The characteristics that make it faster in prokaryotic cells are:
The primary transcript in prokaryotes does not undero further processing, so transation can begin immediatly.
Multiple proteins can be synthetized from a single polycistronic MRNA molecule.
Prokaryotes lack a nuclear envelope, so translation can begin on mRNA even before transcription of the mRNA is complete.
Explanation:
The nature of Prokaryotes makes them undergo the synthesizing process quicker than Eukaryotes because they don't require a preliminary process to start it as Eukaryotes have to undergo one. This is because their composition, Eukaryotes are cells without many organelles like mitochondria or even nucleus. this is also the reason for eukaryotes to be slower in the process of synthesizing mRNA because they don't have organelles to process it faster. Finally, because they don't have a nucleus to help them assimilate the mRNA.
Answer:
C. both a and b are correct
Explanation:
#carry on learning
When yeast rises, it creates air bubbles
Answer:
Need point so here jxhdvzjsnxvhshxjgdyixjgditxkgditxkhdoyxkgdoy c mb CD oydkhxoydkhxuofmhdiy ccx kgfig ydkyd
Explanation: