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Afina-wow [57]
3 years ago
5

Evaluate. 2/3 - 1/6 Please show an explanation.

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
6 0

Answer:

5/6

Step-by-step explanation:

2/3 - 1/6

Find common denominators.

4/6 - 1/6

Subtract.

5/6

Best of Luck!

Scorpion4ik [409]3 years ago
4 0

Answer:

1/2

Step-by-step explanation:

2/3 - 1/6

Get a common denominator of 6

2/3 *2/2 - 1/6

4/6 - 1/6

3/6

Simplify

1/2

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PLEASE ANSWER ASAP LOOK AT THE PICTURE DUE IN 2 SECONDS !!!!!!!!!!!!!!
natima [27]

Answer: its b

Step-by-step explanation:

5 0
2 years ago
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You randomly draw twice from this deck of cards
Serggg [28]

The probability of not drawing C in neither draw is P = 0.5

<h3>How to get the probability?</h3>

All the cards have the same probability of being drawn, in this case, our set of cards is {F, D, C, G}

The probability of not drawing C is equal to the probability of drawing F, D or G. So we have 3 options out of 4, then the probability is:

p = 3/4.

Now we draw another, this time there are 3 cards, one of these is C, and the other two cards are not C. Then the probability of not drawing C again is equal to 2 over 3.

q = 2/3.

The joint probability (for both of these events to happen) is equal to the product of the individual probabilities:

P = p*q = (3/4)*(2/3) = 0.5

If you want to learn more about probability, you can read:

brainly.com/question/251701

3 0
2 years ago
Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!
Nadya [2.5K]

QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

Let us now find the functional value at x=4  

f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}


We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

3 0
3 years ago
Isabelle's book collection contains 15 books, including 6 biographies.
Pachacha [2.7K]

Answer: The probability is 6/15 or 40%

Step-by-step explanation: In your question, you said Isabelle's book collection has 15 books and in that collect she has 6 autobiographies. So they probability as a fraction is 6/15.

8 0
2 years ago
consider the right triangle inside the circle with a center at point E(1,1). which equation can be used to show how he pythagore
Kruka [31]

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where

(h, k) is the center

r is the radius

Since the center is (1, 1), we can write:

(x-1)^2+(y-1)^2=r^2

EG (hypotenuse of the right triangle) is the radius of the circle. Thus, we can say >>>

(x-1)^2+(y-1)^2=(LengthOfEG)^2

The correct answer is

B
6 0
11 months ago
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