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3 years ago

One must combine low resistance with a high number of repetitions to optimally enhance strength.

Biology

2 answers:

lilavasa [31]3 years ago

6 0

Answer:

 Option- B

False

Explanation:

The following statement is not correct or it does not posses any validity as there is a proper mechanism for having the optimally enhanced form of strength, as one must combine low resistance with a high number of repetitions to optimally enhance strength.

Sindrei [870]3 years ago

3 0

Answer:

False

Explanation:

combining low resistance with a high number of repetitions would not optimally enhance your strength hence the statement made is false. to enhance your strength you should combine high resistance with a low number of repetitions when your start and then you can increase the repetitions as your strength improves gradually.

some of the high resistance includes: push ups, sit ups, climbing the stairs, training with waist bands, lifting weights and some other high resistance like cycling. all these will help you build your strength and endurance

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Solnce55 [7]

Answer:

the correct answer is D.

Explanation:

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2 years ago

If a gamete contains 24 chromosomes, how many chromosomes would the somatic cells contain?

Alex787 [66]

Answer:

46 chromosomes are present in somatic cell

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3 years ago

Which statement best describes the relegation ship between proteins and nucleus acids

Novosadov [1.4K]

Answer:

The central dogma of molecular biology best describes the relationship between proteins and nucleic acid.

Explanation:

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3 years ago

Use the key to identify each species. Write the letter of each species (A to G) in the correct

sveticcg [70]

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A dichotomous key is a significantly useful tool to classify organisms. The key provides an easy and fast way for identification by describing different morphological traits, leading you to the correct taxonomic classification.

The key provides morphological descriptions about different taxonomic groups in an easy way to identify these traits in your individual.

The term dichotomous refers to how information is provided. You will always have two options (a and b, or 1 and 2), and you will have to choose one of them according to the characteristics of your organism.

In the exposed example, as the key provides morphological traits, we will separate the organisms into two groups:

the group that has the trait
the group that does not have it.

By recognizing each trait in each of the individuals, we will get to identify the species.

(a) Abdomen with a tail --------------------------- The only option is E

(b) Abdomen without a tail ---------------------- All the others A, B, C, D, F, G

2 ---Only for group A, B, C, D, F, G---

(a) Legs much longer than abdomen and cephalothorax ----------A and G

(b) Legs not much longer than abdomen and cephalothorax----- B, C, D, F

3 ---Only for group A, G---

(a) Hairs on the legs -----------------------------------The only option is A

(b) No hairs on the legs ------------------------------ G

4 ---Only for group B, C, D, F---

(a) Cephalothorax or abdomen segmented ----------------The only option is D

(b) Cephalothorax or abdomen not segmented ----------- B, C, F

5 ---Only for group B, C, F---

(a) Abdomen and cephalothorax of the same size --------The only option is F

(b) Abdomen and cephalothorax of different size -------B, C

6 ---Only for group B, C---

(a) Body covered with long hair ----------------------------------The only option is C

(b) Body not covered with hair ------------------------------------B

A → Tegenaria domestica

B → Ixodes hexagonus

C → Tyroglyphus longior

D → Chelifer tuberculatus

E → Abaliella dicranotarsalis

F → Poecilotheria regalis

G → Odielus spinosus

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2 years ago

What part of the root contains transport tubes?

lana66690 [7]

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3 years ago