A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
Step-by-step explanation:
I am not sure, if something else is missing.
but given that one chart we can say that Craig had 2 fastest throws.
they were in the category 70-75 mph.
but we cannot say precisely which one was faster, and how fast it went.
it is also not clear what is the categorization of a border element (e.g. with an exact speed of 60 mph - is it in the 55-60 or in the 60-65 category ? or both ?).
I assume the upper limit of each interval is included, and the lower limit is excluded.
under this assumption we can say the fastest pitch was faster than 70 mph but slower than or equal to 75 mph.
Answer:
Step-by-step explanation:
This is one minus the probability that all the girls audition for different roles. The total number of ways of assigning roles to the girls is 12^7, because to each of the 7 girls, you have a choice of 12 roles.
Then if each girl is to receive a different role, then there are 12!/5! possibilities for that. If you start assigning roles to the girls, then for the first girl, there are 12 choices, but for the next you have to choose one of the 11 different ones, so 11 for the next, and then one of the 10 remaining for the next etc. etc., and this is 12*11*10*...*6 = 12!/(12-7)! =12!/5!
The probability that a random assignment of one of the 12^7 roles would happen to be one of the 12!/5! roles where each girl has a different role, is
(12!/5!)/12^7 = 12!/(12^7 5!)
Then the probability that two or more girls addition for the same part is the probability that not all the girls are assigned different roles, this is thus:
1 - 12!/(12^7 5!)
Answer:
For the First one, 2 + 9 = 11. And 11 - 3 + (-19) = -11
Step-by-step explanation:
do you mean 2x squared? If so, x = 5, -5
