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poizon [28]
3 years ago
12

Find the distance between the two points rounding to the nearest tenth if necessary (-1,4) and (4,-8)

Mathematics
1 answer:
laila [671]3 years ago
5 0

Answer:

13 units

Step-by-step explanation:

\sqrt{(4--1)^{2}+(-8-4)^{2}  }

=\sqrt{5^{2}+(-12)^{2} }

=\sqrt{25 + 144}

=\sqrt{169}

=13 units

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Make x the subject of m=n + x/p
marshall27 [118]

Answer:

\boxed{x = p(m - n)}

Step-by-step explanation:

=  > m = n +  \frac{x}{p}  \\  \\  =  > m = (n \times  \frac{p}{p} ) +  \frac{x}{p}  \\  \\  =  > m =  \frac{pn}{p}  +  \frac{x}{p}  \\  \\  =  > m =  \frac{pn + x}{p}  \\  \\  =  > mp = pn + x \\  \\  =  > x + pn = pm \\  \\  =  > x = pm - pn \\  \\  =  > x = p(m - n)

4 0
3 years ago
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Alex_Xolod [135]
Answers

1. B) 31
2. B) 4
3. A) 15
4. D) 24
5. A) 3

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7 0
2 years ago
3z-4=6z-17 how do solve
Maru [420]
3z-4=6z-17
-3z-4=-17 (subtracted the 6z from both sides)
-3z=-13 (added the 4 to both sides)
z=\frac{-13}{-3z} (divided both sides by -3z)
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5 0
3 years ago
Read 2 more answers
the second term of a geometric sequence is 18 and the fourth term is 8 find the common ratio . And find the sum of the first 6 t
777dan777 [17]

Answer:

  • ratio: 2/3
  • sum: 73 8/9

Step-by-step explanation:

The general term of a geometric sequence is ...

  an = a1·r^(n-1)

You have the 2nd and 4th terms, so ...

  a2 = a1·r^(2-1) = a1·r

  a4 = a1·r^(4-1) = a1·r^3

We can find r from the ratio ...

  a4/a2 = (a1·r^3)/(a1·r) = r^2 = 8/18 = 4/9

Then r is ...

  r = √(4/9) = 2/3 . . . . the common ratio

The first term is ...

  a2 = 18 = a1·(2/3)

  a1 = (3/2)·18 = 27

__

The sum of the first 6 terms is ...

  Sn = a1·(r^n -1)/(r -1)

  S6 = 27·((2/3)^6 -1)/(2/3 -1)

  S6 = 27·(64/729-1)/(2/3-1) = (27)(665)/243 = 73 8/9

The sum of the first 6 terms is 73 8/9.

_____

<em>Check on the sum</em>

The first 6 terms are ...

  27, 18, 12, 8, 5 1/3, 3 5/9

Their sum is 73 8/9, as above.

8 0
3 years ago
HELP
Amiraneli [1.4K]

Answer:

volume of a cone = 1/3*(πr²h)

Step-by-step explanation:

6 0
2 years ago
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