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Alex Ar [27]
3 years ago
8

Help me with this problem please . X=b-cd solve for c

Mathematics
2 answers:
Yanka [14]3 years ago
8 0
<span>
c = (b - x) / d
Hope this helped!</span>
podryga [215]3 years ago
5 0
X = b - cd
cd = b - x
c = (b - x) / d

So, your final answer is c = (b - x) / d

Hope this helps!
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The point where two rays meet to form an angle is called the _______________.
Alenkinab [10]
<span>The point where two rays meet to form an angle is called the
Vertex
and vertex became an angle
the corner of polygon are also called vertex
so i conclude option A is correct from above
hope it helps</span>
4 0
3 years ago
the length of a rectangle is 4in more than its width, and its perimeter is 34in find the length and width of the rectangle ​
Anna [14]

Let l and w be, respectively, the length and the width of the rectangle.

If the length is 4 inches more than the width, we have

l = w+4

Moreover, the perimeter of a rectangle is given by

2(l+w)

And we can substitute l=w+4 to get

2(w+4+w)=2(2w+4)=4w+8

We know that the perimeter is 34 inches:

4w+8=34 \iff 4w = 26 \iff w = \dfrac{26}{4}=6.5

Which implies

l=w+4=6.5+4=10.5

5 0
4 years ago
Find the value of p in this equation. 2/5p+p=5​
Ganezh [65]

Answer:

p=\frac{25}{7}

Step-by-step explanation:

Greetings!

I'm~Isabelle~Williams~and~will~be~answering~your~question!

(\frac{2}{5}p+p )=5            ~~~~~(Combine ~the~like~terms)

\frac{7}{5}p=5

Then~multiply~both~sides~by~\frac{5}{7}:

(\frac{5}{7} )\times(\frac{7}{5}p )=(\frac{5}{7} )\times(5)

p=\frac{25}{7}

Hope~my~answer~helps~you!~feel~free~to~ask~further~question.

-Isabelle~Williams

4 0
3 years ago
Find the area of each shaded segment in nearest tenth.
shepuryov [24]

Answer:

Denote the center of circle as O, the 2 endpoints of shaded segment as AB, then we have:

section OAB area = pi x radius^2 x (120/360) = pi x 6^2 x (1/3) = 37.7 (cm2)

Considering triangle OAB, we have OA = OB = radius, angle AOB = 120 deg. Denote OH as the height of triangle. H lies on AB.

=> Applying cosine and sine theorem in right triangle AHO:

OH = OA x cos 60 = 6 x (1/2) = 3 (cm)

AH = OA x sin 60 = 6 x (sqrt3)/2 = 5.2 (cm)

=> triangle AOB area:

A = triangle AOH area x 2

   = AH x OH x (1/2) x 2 = 3 x 5.2 x (1/2) x 2 = 15.6 (cm2)

=> shaded segment area = section OAB area - triangle AOB

                                          = 37.7 - 15.6 = ~21.1 (cm2)

Hope this helps!

:)

7 0
3 years ago
PLEASE, I HAVE POSTED THIS QUESTION OVER 5 DIFFERENT TIMES AND STILL HAVEN'T GOTTEN AN ANSER PLEASE HELP IF YOU CAN!!!!!!!!!!!!!
Lemur [1.5K]

Answer:

10 sqrt(3)/3 =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side /adj side

tan 30 = x/10

10 tan 30 =x

10 ( sqrt(3)/3) = x

10 sqrt(3)/3 =x

6 0
3 years ago
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