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dlinn [17]
3 years ago
5

PLEASE HELP ME!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

a) 4 - vt - d = \frac{1}{2} at^{2}

b) 1 - 2(vt - d) = at^{2}

c) 6 - \frac{2(vt - d)}{t^{2}} = a

Step-by-step explanation:

It simply asks the steps to go from the original displacement formula to isolate a (the acceleration).  It's just a matter of moving items around.

We start with:

d = vt - \frac{1}{2} at^{2}

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

vt - d = \frac{1}{2} at^{2}

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

2(vt - d) = at^{2}

Finally, we divide each side by t^2 to isolate a (answer #6):

\frac{2(vt - d)}{t^{2}} = a

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Solve 3 -x = 243 -5 1/5 5
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Help Q-Q 7/10c =4 1/5
shepuryov [24]

\huge\mathfrak\green{answer}

= q -   \frac{q7}{10} c =  \frac{41}{5}

\red{multiply}

= q -  \frac{cq7}{10} =  \frac{41}{5}

\red{subtract \: q \: from \: both \: sides}

= q -  \frac{cq7}{10}  - q =  \frac{41}{5} - q

\red{now \: simplify}

=  -  \frac{cq7}{10}  =  \frac{41}{5}  - q

\red{multiply \: 10 \: both \: sides}

= 10( -  \frac{cq7}{10} ) = 10. \frac{41}{5}  - 10q

\red{simplify}

=  - cq7 = 82 - 10q

\red{now \: divide}

=  \frac{ - cq7}{ - q7}  -  \frac{82}{ - q7}  -  \frac{10q}{ - q7}

\red{simplify}

= c =   - \frac{82 - 10q}{q7} (q≠0)

Brainliest? :) (I'd really appreciate if you mark me as brainliest)

\huge\mathfrak\green{thank \: you}

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