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dlinn [17]
3 years ago
5

PLEASE HELP ME!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

a) 4 - vt - d = \frac{1}{2} at^{2}

b) 1 - 2(vt - d) = at^{2}

c) 6 - \frac{2(vt - d)}{t^{2}} = a

Step-by-step explanation:

It simply asks the steps to go from the original displacement formula to isolate a (the acceleration).  It's just a matter of moving items around.

We start with:

d = vt - \frac{1}{2} at^{2}

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

vt - d = \frac{1}{2} at^{2}

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

2(vt - d) = at^{2}

Finally, we divide each side by t^2 to isolate a (answer #6):

\frac{2(vt - d)}{t^{2}} = a

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Step-by-step explanation:

From similar triangles, see diagram in attachment

\frac{r}{4}=\frac{h}{16}


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r=\frac{h}{4}


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Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means h=8cm.


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