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cricket20 [7]
2 years ago
10

A box contains five red balls, six green ones, and nine yellow balls. Suppose you select one ball at random from the box and do

not replace it. Then you randomly select a second ball. Find the probability that both balls will be red?
Mathematics
1 answer:
Tanya [424]2 years ago
8 0

Answer:1/19

Step-by-step explanation:

Number of red balls: 5

Number of green balls: 6

Number of yellow balls: 9

Total number of balls= 5+6+9= 20

Let probability of red balls = Pr(red balls)

PR(red balls)= 5/20

Hence probability of picking first ball as red = 5/20

Probability of picking second ball without replacing the first ball:

This implies that by picking second ball to be red, the number of red ball would decrease by 1. Also the total number of balls would also decrease by 1 because it isn't replaced.

PR(2nd ball) = 4/19

Pr(1st ball red and 2nd ball red)= 5/20 * 4/19

=(5*4)/(20×19)

20/(20/19)

= 1/19

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A door of a lecture hall is in a parabolic shape. The door is 56 inches across at the bottom of the door and parallel to the flo
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The parabolic shape of the door is represented by y - 32 = -\frac{2}{49}\cdot x^{2}. (See attachment included below). Head must 15.652 inches away from the edge of the door.

Step-by-step explanation:

A parabola is represented by the following mathematical expression:

y - k = C \cdot (x-h)^{2}

Where:

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k - Vertical component of the vertix, measured in inches.

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For the design of the door, the parabola must have an absolute maximum and x-intercepts must exist. The following information is required after considering symmetry:

V (x,y) = (0, 32) (Vertix)

A (x, y) = (-28, 0) (x-Intercept)

B (x,y) = (28. 0) (x-Intercept)

The following equation are constructed from the definition of a parabola:

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The parabolic shape of the door is represented by y - 32 = -\frac{2}{49}\cdot x^{2}. Now, the representation of the equation is included below as attachment.

At x = 0 inches and y = 22 inches, the distance from the edge of the door that head must observed to avoid being hit is:

y -32 = -\frac{2}{49} \cdot x^{2}

x^{2} = -\frac{49}{2}\cdot (y-32)

x = \sqrt{-\frac{49}{2}\cdot (y-32) }

If y = 22 inches, then x is:

x = \sqrt{-\frac{49}{2}\cdot (22-32)}

x = \pm 7\sqrt{5}\,in

x \approx \pm 15.652\,in

Head must 15.652 inches away from the edge of the door.

8 0
3 years ago
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