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Alecsey [184]
3 years ago
14

What are the large objects that revolve around the Sun called?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
6 0
A. Planets
Are what revolves around the sun
tia_tia [17]3 years ago
3 0

Answer:

A) planets

Step-by-step explanation:

planets revolve around the sun

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450 yards in 15 minutes?
madam [21]

Answer:

30 yards per minute.

Step-by-step explanation:

Unit rate is basically when the denominator is 1. In this case, 450 is divisible by 15, so if you divide that, you get 30.

4 0
3 years ago
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The question is in the photo
vovikov84 [41]

\displaystyle\bf 3x+7\geq 52 \ ; \ x>15 \\\\3x\geq 45\\\\x\geq 15 \ \ \ and  \ \ \ x>15 here is a contradiction because in one inequality x can be equal to 15 ; and in the other it cannot

6 0
3 years ago
Rewrite -5(x+3) without parentheses
nevsk [136]

Answer:

-5x-15

Step-by-step explanation:

its simple you have to multiply it to both

6 0
3 years ago
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Please help fast and explain how you got the answer if you do that I will give you the crown and 5 star if you do anything other
Brums [2.3K]

Answer:

what do you need help with? there is no question

Step-by-step explanation:

7 0
2 years ago
Find where the slope of the curve is defined:<br> x^2y-xy^2=4
Natali [406]
You do the implcit differentation, then solve for y' and check where this is defined. 
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0 
Solve for y': y'(x²-2xy) +2xy - y² = 0 
y' = (2xy-y²) / (x²-2xy) 
Check where defined: y' is not defined if the denominator becomes zero, i.e. 
x² - 2xy = 0 x(x - 2y) = 0 
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y: 
0^2*y - 0*y^2 =? 4 0 =? 4 
This is impossible, hence the function is not defined for 0, and we can disregard this. 
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16) 
This is a possible value for y, so we have a point where y is defined, but not y'. 
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-). 
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...). 
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function). 
3 0
4 years ago
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