3 years ago

The question is in the photo

1 answer:

6 0

$\displaystyle\bf 3x+7\geq 52 \ ; \ x>15 \\\\3x\geq 45\\\\x\geq 15 \ \ \ and \ \ \ x>15$ here is a contradiction because in one inequality x can be equal to 15 ; and in the other it cannot

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