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stiv31 [10]
3 years ago
11

The question is in the photo

Mathematics
1 answer:
vovikov84 [41]3 years ago
6 0

\displaystyle\bf 3x+7\geq 52 \ ; \ x>15 \\\\3x\geq 45\\\\x\geq 15 \ \ \ and  \ \ \ x>15 here is a contradiction because in one inequality x can be equal to 15 ; and in the other it cannot

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