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strojnjashka [21]
3 years ago
5

Please help me it due tonight and I was babysitting all day and I have a headache. Plzzz help me.

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

is this a test or a ongoing pratice or study guide

Step-by-step explanation:

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What is Xavier’s available lot coverage?
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<h2> <em><u>720</u></em><em><u>0</u></em></h2>

Step-by-step explanation:

<h3>At first:</h3>

<em><u>G</u></em><em><u>i</u></em><em><u>v</u></em><em><u>e</u></em><em><u>n</u></em><em><u>,</u></em>

Back of lot of the trapezoid = 175

Front of lot of the trapezoid = 185

Length of lot of the trapezoid = 100

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em>

Area of the trapezoid

=  \frac{a + b}{2} c

  • <em>[</em><em>On</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>values</em><em>]</em>

=  \frac{175 + 185}{2}  \times 100

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

= 360 × 50

  • <em>[</em><em>On multiplying</em><em>]</em>

= 18000

<em><u>Hence</u></em><em><u>,</u></em>

We got the <em>T</em><em>otal Area </em><em>as</em><em> </em><em>180</em><em>0</em><em>0</em><em>.</em>

<h3>Now:</h3>

<em><u>As</u></em><em><u> </u></em><em><u>per</u></em><em><u> </u></em><em><u>given</u></em><em><u> </u></em><em><u>equation</u></em><em><u>,</u></em>

  • \frac{40}{100}  =  \frac{x}{total \: area}
  • To find the value of x

<em><u>Solution</u></em><em><u> </u></em><em><u>,</u></em>

=  > \frac{40}{100}  =  \frac{x}{total \: area}

  • <em>[</em><em>On</em><em> </em><em>putting</em><em> </em><em>Total</em><em> </em><em>Area</em><em> </em><em>=</em><em> </em><em>180</em><em>0</em><em>0</em><em>]</em>

=  > \frac{40}{100}  =  \frac{x}{18000}

  • <em>[</em><em>On</em><em> </em><em>cross</em><em> </em><em>multiplication</em><em>]</em>

=> 40 × 18000 = 100 × x

  • <em>[</em><em>O</em><em>n</em><em> </em><em>Simplification</em><em> </em><em>]</em>

=> 720000 = 100x

  • <em>[</em><em>On</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>100</em><em>]</em>

=  >  \frac{720000}{100}  =  \frac{100x}{100}

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em> </em><em>]</em>

=> x = 7200

<em><u>Hence</u></em><em><u>,</u></em>

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