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Snowcat [4.5K]
3 years ago
6

5(2 + 9) + 62 help meeee plss

Mathematics
2 answers:
PIT_PIT [208]3 years ago
4 0

Answer:

117

Step-by-step explanation:

vredina [299]3 years ago
4 0

Answer:

117

Step-by-step explanation:

( 5x2=10, 5x9=45 ) - distributive property

then add 62 to get 117

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What is the Surface Area and volume of this cylinder?
Dmitriy789 [7]

Answer:131

Step-by-step explanation:

hope this helps <3

3 0
2 years ago
Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
Evelina took 50 people fishing each day last week. The table shows the number of fish the group caught each day.
Alisiya [41]

Answer:

152

Step-by-step explanation:

The amount of fish caught is at a constant decreasing rate of 17. 203-186=17, 186-169=17, 169-17=152. So all you have to do is subtract the constant rate from the last known number.


8 0
3 years ago
Read 2 more answers
the hypotenuse of a triangle is one foot more than twice the length of the shorter legal. the longer leg is seven feet longer th
wolverine [178]
8, 15, 17

You can do this by using the Pythagorean Theorem and setting the sides equal to

shorter leg = x
longer leg = x + 7
hypotenuse = 2x + 1

Then solve so that one side is equal to zero and use the quadratic formula.
6 0
3 years ago
Read 2 more answers
Aidan is paying his taxes and realizes that he was in the first tax bracket (10%) last year. Eleven years ago, he bought a commo
Makovka662 [10]
So let us analyze the given table above. In the first tax bracket, he doesn't have to pay tax on the dividends. The $565 he earned in dividends is not taxable as well. Also the common stock he bought for $705 since this is a long term evidence. So the only taxable would be <span>$780 in coupons on a corporate bond. So multiply this by 10% and you get $78. Therefore, the answer would be the first option. Hope this helps.</span>
3 0
3 years ago
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