there are many combinations for it, but we can settle for say
![\bf \begin{cases} f(x)=x+2\\[1em] g(x)=\cfrac{9}{x^2}\\[-0.5em] \hrulefill\\ (f\circ g)(x)\implies f(~~g(x)~~) \end{cases}\qquad \qquad f(~~g(x)~~)=[g(x)]+2 \\\\\\ f(~~g(x)~~)=\left[ \cfrac{9}{x^2} \right]+2\implies f(~~g(x)~~)=\cfrac{9}{x^2}+2](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20f%28x%29%3Dx%2B2%5C%5C%5B1em%5D%20g%28x%29%3D%5Ccfrac%7B9%7D%7Bx%5E2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20%28f%5Ccirc%20g%29%28x%29%5Cimplies%20f%28~~g%28x%29~~%29%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20f%28~~g%28x%29~~%29%3D%5Bg%28x%29%5D%2B2%20%5C%5C%5C%5C%5C%5C%20f%28~~g%28x%29~~%29%3D%5Cleft%5B%20%5Ccfrac%7B9%7D%7Bx%5E2%7D%20%5Cright%5D%2B2%5Cimplies%20f%28~~g%28x%29~~%29%3D%5Ccfrac%7B9%7D%7Bx%5E2%7D%2B2)
- Rounding 789 nearest to tens will be 790.
Step-step Explanation:
Let's know how to round any number nearest to tens (Rules):-
We know tens place in any no. from left is at second place and number right to tens place need to be changed as:-
- If last digit is 0, then we don't have to do any rounding, because it is already to the ten.
- We round the no. down to the nearest ten if the last digit in the no. is 1, 2, 3, or 4
- We round the no. up to the nearest ten if the last digit in the no. is 5, 6, 7, 8, or 9.
4/15
Multiple the numerator by numerator, and denominator by denominator, then simplify
It would be 625 because 5 to the fourth power is 5×5×5×5×5 which is equal to 3,125 and then it would be 3,125 over 5 which is 3,125÷5 which is equal to 625 so the answer would be 625
Step-by-step explanation:
7 × 6 = 42 Answer
hope it helps
