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yarga [219]
3 years ago
12

Relay Race Results

Mathematics
1 answer:
yulyashka [42]3 years ago
3 0

93

because if the team second wones the match with two points then the answer will be 93

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A circle has a diameter of 4 inches. A square has a side length of 4 inches. What is true about the areas of these two figures?
Nuetrik [128]
The area of the square is greater than the circle: the area of the circle is pi(r)^2 while the area of the square is length times width. The area of the circle is about 12.5 while the area of the square is 16.
4 0
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Help pls please hmmm​
hichkok12 [17]

Step-by-step explanation:

Here is your answer

  • (2)⁴*³
  • 2¹²

6 0
3 years ago
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-11 2/3 × ( -4 1/5 )=​
galina1969 [7]
The answer is 49
Solving Steps

8 0
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PLEASE HELP!!!! <br><br> Given f(x).... what is lim f(x)?
irakobra [83]

Answer:

\pi

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Pls only do this if yk it because i’m giving correct answer brainliest! :))
Leno4ka [110]

Answer:

x=2+\frac{1}{2}\sqrt[]{21}

or

x=2-\frac{1}{2}\sqrt{{21}

Step-by-step explanation:

4x^2-16x-26=-21

Add 21 on both sides.

4x^2-16x-26+21=-21+21

4x^2-16x-5=0

a=4

b=-16

c=-5

x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac}  }{2a}

x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)}  }{2(4)}

x=\frac{16\frac{+}{}\sqrt[]{256+80}  }{8}

x=\frac{16\frac{+}{}\sqrt[]{336}  }{8}

x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21}  }{8}

x=\frac{16\frac{+}{}2*2\sqrt[]{21}  }{8}

x=\frac{16\frac{+}{}4\sqrt[]{21}  }{8}

---------------------------------------------------------------------------

x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}

x=2+\frac{1}{2}\sqrt[]{21}

---------------------------------------------------------------------------

x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}

6 0
3 years ago
Read 2 more answers
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