Answer:
f(x) = -3(x+3)(x-1)
Step-by-step explanation:
x = -3 & 1; f(x) = 9
f(x) = a(x-r1)(x-r2)
f(0) = a(x-r1)(x-r2) = 9; 9 = a(0-(-3))(0-1)
9 = a(3)(-1); 9 = a(-3)
a = -3
f(x) = -3(x+3)(x-1)
Answer:
Domain: the set of possible values of the independent variable or variables of a function.
Range: the set of values that a given function can take as its argument varies.
Step-by-step explanation:
Hopefully this helps ik it was confusing to me too in pre-algebra when i was in 8th grade
have a great day
If you would like to write a * b + c in simplest form, you can do this using the following steps:
a = x + 1
b = x^2 + 2x - 1
c = 2x
a * b + c = (x + 1) * (x^2 + 2x - 1) + 2x = x^3 + 2x^2 - x + x^2 + 2x - 1 + 2x = x^3 + 3x^2 + 3x - 1
The correct result would be x^3 + 3x^2 + 3x - 1.
